Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Step-by-step explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now, 
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average
Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Answer:
x - 8>-4-x
Step-by-step explanation:
Looking at x - 8>-4-x
Collect the like terms;
x+x > -4 + 8
2x < 4
x > 4/2
x < 2
Since the values of x are greater than 2,this shows that they are positive values and will be farther from -8 than -4
Answer:
$5.76
Step-by-step explanation:
Prinkpal balance = $24^4^6% =5.76
They can’t be similar. Similar triangles have congruent corresponding angles, and two angles are given on each. Neither of those correspond to another on the opposite triangle. Basically, there’s no way to have three congruent angles, so they aren’t similar.
The answer is 6 with a remainder of 1. (6 R.1)
Hope this helps!!
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