Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.
Let x be the height of the flagpole, then
Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
okay. the point has an x and y value. place them into the equation.
1=m(1)+b
m=slope, and theequation tells you that slope is 7.
1=7(1)+b
now you need to figure out what b is.
1=7(1)+b
^
1= 7 +b
-7 -7
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-6=B
b is 6. now place it into the equation, replacing the x and y values back.
y=7x-6.
write 7 and 6 in the boxes (the negative for the six has already been provided)
Answer:
In the 3rd and 4th quadrants of the coordinate system
ie π < θ < 2π. At π and 2π the sine values are zero
Step-by-step explanation:
Answer:
x = -5/31
Step-by-step explanation:
5(5x + 1) = 3x - 9x multiply 5 with the inside of the parenthesis, 5(5x + 1) = 25x + 5
25x + 5 = 3x - 9x add the like terms, 31x = -5 and x = -5/31
