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3 years ago

Please help!!!!!!!!!!!!!!

Mathematics

1 answer:

Goryan [66]3 years ago

4 0

Answer:

choice A is the answer

Step-by-step explanation:

$5 + 2.75s \leqslant 21 \\ 2.75s \leqslant 21 - 5 \\ s \leqslant 16 \div 2.75 \\ s \leqslant 5.82$

but since we only can have a whole number in the number of stops, she can only travel 5 stops with the money she has.

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line L passes through point (2, -5) and is perpendicular to the line with equation y=7. determine the equation of line L

Andrew [12]

Answer:

The equation of the line L is $x=2$

Step-by-step explanation:

we know that

The line y=7

Is a horizontal line (parallel line to the x-axis)

The slope of a horizontal line is equal to zero

A line L perpendicular to the given line must be a vertical line (parallel to the y-axis)

The slope of the line L is undefined

The line L passes through the point (2,-5)

therefore

The equation of the line L will be equal to the x-coordinate of the given point

$x=2$

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3 years ago

The midpoint between 94.68 and 49.67

Brilliant_brown [7]

Answer:

72.175

Step-by-step explanation:

The first step is subtract 94.68 by 49.67 which would be 45.01

The next step would be to use 45.01 and divide by two

The last step would be subtract 94.68 by 22.505 and you would get 72.175

Therefore your answer would be 72.175

8 0

4 years ago

Write a decimal that is 1/10 of .9

amm1812

1/10 of .9 is the same as dividing .9 by 10. .90 / 10 = .09 .09 is the answer

8 0

3 years ago

Slope = 1 y-intercept = 3

Vedmedyk [2.9K]

Answer:

y = x + 3

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

1x is the same as x

6 0

3 years ago

Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation

evablogger [386]

Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)

$sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} \\ \\ \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} )=1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\ cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\$
$2cos(x)sin\frac{ \pi }{4} =1 \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2} \\ 2cos(x) \frac{ \sqrt{2} }{2} =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x) =1 \\ \sqrt{2} cos(x)=1 \\$
$cos(x)= \frac{1}{ \sqrt{2} } \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z$

6 0

3 years ago