The answer is A B AND D mark me brainliest?
Answer:
Explanation:
The following code is written in Java. It creates the Bug class with the position and direction variables. Then it creates a constructor, move method, turn method, and getPosition method. Finally, a bug object called bugsy is created in the main method, and we move it once to the right, then again to the right, and then we turn it and move it 5 times to the left, printing out the position when it is done moving. Output can be seen in the attached picture below.
class Brainly {
public static void main(String[] args) {
Bug bugsy = new Bug(10);
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
bugsy.turn();
bugsy.move();
bugsy.move();
bugsy.move();
bugsy.move();
bugsy.move();
System.out.println("Current bug position: " + bugsy.getPosition());
}
}
class Bug {
char direction = 'r';
int position = 0;
public Bug(int initialPosition) {
this.position = initialPosition;
}
public void turn() {
if (this.direction == 'r') {
this.direction = 'l';
} else {
this.direction = 'r';
}
}
public void move() {
if (this.direction == 'r') {
this.position += 1;
} else {
this.position -= 1;
}
}
public int getPosition() {
return this.position;
}
}
Answer:
See below
Explanation:
Because sometimes you have to 'carry' a 1 over to the ext column when adding two binary numbers
Example :
1 1 1
<u>+1 1 1 </u> <==== starting in the first R column add 1 + 1 to get 0 and carry 1
then the next column you will add 1 + 1 + 1 = 1 and carry 1 again
then 1 + 1 + 1= 1 and carry 1 again (to column 4) to get
1 1 1 0
a = int(input("Class A tickets sold: "))
b = int(input("Class B tickets sold: "))
c = int(input("Class C tickets sold: "))
print("Total income generated: $"+str((a*20)+(b*15)+(c*10)))
I hope this helps!
In psuedocode it would be:
length = input()
width = input()
area = length * width
print(area + " sq ft");