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Maru [420]
3 years ago
6

What are some hazards of being an astronomer??

Computers and Technology
1 answer:
mariarad [96]3 years ago
3 0
Are you going into space... if so well... space, that is the big issue

You might be interested in
Write a repetition statement that outputs the numbers 45 , 51 , . . . , 165 . That is, all of the multiples of 6 in increasing o
Bingel [31]

Answer:

#include <iostream>

using namespace std;

int main()

{

   int i = 45;

   for ( i = 45; i <=165; i = i + 6)

       cout << i << endl;

}

Explanation:

I corrected your code and highlighted the mistakes. Even though you wrote the correct algorithm, your code did not compile because of the typos you made.

Remember, C++ is a case-sensitive language. That means, "For" is not same as "for".

Generally, variables and keywords are written in lower case. Of course, there are exceptions, such as constant variables are all written in uppercase letter and class names start with an uppercase letter.

8 0
3 years ago
Write a Java program to create a class called Cars. The class should include three instance variables: makes (type: String), mod
Fiesta28 [93]

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

5 0
3 years ago
Which steps of the management science process can either be a recommended decision or information that helps a manager a decisio
Step2247 [10]
Probably c or a with the question your asking
8 0
2 years ago
1.
Vlad1618 [11]
A. Since it tells about how people think she’s lesser because she’s a women.
7 0
3 years ago
Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
4 0
3 years ago
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