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jonny [76]
3 years ago
11

Combination of star topology and star topology can consider as hybrid?​

Computers and Technology
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

no

Explanation:

A hybrid topology is a type of network topology that uses two or more differing network topologies. These topologies can include a mix of bus topology, mesh topology, ring topology, star topology, and tree topology.

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Write a program in java to enter a character.The program displays the message "uppercase vowel" if entered character is uppercas
horrorfan [7]

Answer:

d

Explanation:

i think

3 0
3 years ago
You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

  • To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0
3 years ago
February 1995, Kevin Mitnick was arrested. While on parole was he allowed to have a phone or computer?
m_a_m_a [10]

Answer:

He was not allowed on a phone of computer after being arrested.

Explanation:

If you read about it he wasn't even allowed to work at 7-11 because of an electronic cash register.

6 0
3 years ago
Read 2 more answers
Just a quick question, how do you set something == to char and int in an if statement (java)
Troyanec [42]

This is the requested code in java.

public class <em>CharTest</em> {

   public static String checkCharacter(String text, int index) {

       if (0 <= index && index <= text.length()) {

           char ch = text.charAt(index);

           if (Character.isLetter(ch)) {

               return ch + " is a letter";

           } else if (Character.isDigit(ch)) {

               return ch + " is a digit";

           } else if (Character.isWhitespace(ch)) {

               return ch + " is a whitespace character";

           } else {

               return ch + " is an unknown type of character";

           }

       } else {

           return "index " + index.toString() + " is out of range";

       } // <em>end if</em>

   } // <em>end function checkChar()</em>

   public static void <em>main</em>(String[] args) {

       // <em>Test the three samples from the specification.</em>

       System.out.println(<em>checkCharacter</em>("happy birthday", 2));

       System.out.println(<em>checkCharacter</em>("happy birthday", 5));

       System.out.println(<em>checkCharacter</em>("happy birthday 2 you", 15));

   } // <em>end function main()</em>

} // <em>end class CharTest</em>

The function <em>checkcharacter</em>(text, index) returns a string value describing the kind of character found at the position in text specified by index; whether it was a letter, digit, whitespace, or an unknown kind of character.

How it does that is to make use of respective functions defined within the Character class in java. That is

  • isLetter(char) returns a bool specifying if the char parameter is a letter.
  • isDigit(char) returns a bool specifying if the char parameter is a digit.
  • isWhitespace(char) returns a bool specifying if the char parameter is a whitespace character.

It calls these functions in an if statement. These else part of the if statement is then executed if the character is neither a <em>letter</em>, <em>digit</em>, or <em>whitespace</em>.

Finally, the function main() calls <em>checkCharacter</em>() three times to test the function and return the results to the console.

Another example of a java program on characters is found in the link below

brainly.com/question/15061607

3 0
3 years ago
Define an interface GUIComponent consisting of four method declaration: open: void-returning, accepts no parameters close: both
Lesechka [4]

Answer:

interface GUIComponent{

  public void open();

  public boolean close();

  public void resize(int width, int height);

  public void move(int x, int y);

}

Explanation:

3 0
3 years ago
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