Answer: ABCD is a quadrilateral
To prove : ∠AOB=
2
1
(∠C+∠D)
AO and BO is bisector of A and B
∠1=∠2∠3=∠4...(1)
∠A+∠B+∠C+∠D=360
(Angle sum property)
2
1
(∠A+∠B+∠C+∠D)=180...(2)
In △AOB
∠1+∠3+∠5=
2
1
(∠A+∠B+∠C+∠D)
∠1+∠3+∠5=∠1+∠3+
2
1
(∠C+∠D)
∠AOB=
2
1
(∠C+∠D)
Explanation: In a quadrilateral ABCD. AO and BO are bisectors of angle A and angle B respectively. Prove that ∠AOB=
2
1
{∠C+∠D}.
Answer:
-1 = 1/3 * 6 - 3
Step-by-step explanation:
So if it goes through point (6, -1) and has a slope of -1/3, all of this is parts of the slope intercept equal, Y = mx - B. You have the slope, which is m in the equation, y = -1/3 x - b. you already have a y and x which are the points passed, -1 = -1/3 * 6 - b, but this can't equal y, so you must have did it wrong, the only way this could equal y is if the slope wasn't negative, and in that case it would be -1 = 1/3 * 6 - 3. Because 1/3 * 6 is 2 and then subract 3 and you get -1.
6/276 = 0.022
Or if you want a simplified fraction, then 1/46
Answer:
V= 628.32
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
(6^2) -5(6) -2 =4
that is the answer
