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3 years ago

Fraction 3•5 • fraction 4•9 =

Mathematics

2 answers:

Nastasia [14]3 years ago

7 0

Answer:

Step-by-step explanation:

3.5×4.9

=35/10×49/10

=1715/100

Or 17.15 answer

astra-53 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

3/5 times 4/9. multiply straight across. 3 times 4 is 12. 5 times 9 is 45. your answer is 12/45. but this answer can be simplified if we take out a 3 for each one. so you have 4/15

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Alx+b) = 4x + 10

Leokris [45]

Answer:

a=4, b=5/2

Step-by-step explanation:

Assuming the given equation is

$a(x + b) = 4x + 10$

We expand the left hand side to get:

$ax + ab = 4x + 10$

If this equation must have infinitely many solutions, then

$ax = 4x \\ \implies \: a = 4$

Also we must have

$ab = 10$

Put a=4 to get:

$4b = 10$

$b = \frac{10}{4} = \frac{5}{2}$

3 0

3 years ago

ASE

eimsori [14]

Answer:

128 deg

Step-by-step explanation:

The sum of the measures of the angles of a polygon of n sides is

(n - 2)180

A trapezium has 4 sides, so the sum of the measures of the angles is

(4 - 2)180 = 2(180) = 360

m<CBE + m<C + m<D + m<DEB = 360

Angles ABC and CBE are a linear pair so the sum of their measures is 180 deg.

m<ABC + m<CBE = 180

115 + m<CBE = 180

m<CBE = 65

m<C = x

m<D = 90

Angles DEB and DEF are a linear pair so the sum of their measures is 180 deg.

m<DEB + m<DEF = 180

m<DEB + m<103 = 180

m<DEB = 77

m<CBE + m<C + m<D + m<DEB = 360

65 + x + 90 + 77 = 360

x + 232 = 360

x = 128

Answer: 128 deg

3 0

3 years ago

Read 2 more answers

Find an irrational number between -10 and -10.1.

Pavlova-9 [17]

Between two rational numbers there are an infinite number of irrational numbers.

Example:

$- 5 \sqrt{3} -\sqrt{2}= 5 \times 1.7320508 - 1.41421356 \approx -10.0744676\\\\
-10.1 \ \textless \ -10,0744676 \ \textless \ -10$

6 0

3 years ago

A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio

Klio2033 [76]

Answer:

k = 0.032
P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

$P(t)=P_0\cdot e^{kt}$

We know from the given points that we can write the equation as ...

$P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t$

Comparing this to the desired form, we see that ...

$P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693$