The graph of the equations was plotted using geogebra graphing and attached.
Let x represent the hours weightlifting and y represent the hours doing cardio exercises.
Since he spend a maximum of 20 hours, hence:
x + y ≤ 20 (1)
Also, he spends at least 8 of those hours weightlifting, hence:
x ≥ 8 (2)
He wants to spend no more than 15 hours doing cardio exercises, this is:
y ≤ 15 (3)
The graph of the equations was plotted using geogebra graphing and attached.
Find out more at: brainly.com/question/17178834
Answer:
43
Step-by-step explanation:
you change the 1 hour into minute you and 60min to 25 minutes and then you subtract from 42 minutes to get the solution
First one:
you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so
when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)
-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m
add
-10m-13m+2m^4-20m^4
-23m-18m^4
second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms
(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8
10 Inches
A = p q / 2
p = diagonal 1
q = diagonal 2
2A / q = p
Solve for p
180/18 = 10
