Hello!
If Bruce observes that the number of pitches a batter hits varies and is given by the function f(x)=x-11, and the batters get {4, 12, 14, 27, 42}, then Bruce threw {15, 23, 25, 38, 53} pitches. We get this solution set by adding 11 to each element in the set {4, 12, 14, 27, 42}.
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To calculate expected value,
We can add up the probability of all possible events.
The 2 possible events are either winning $50 or losing the prize, which is $ - 50
Expected value =
50 x 40 % + (-50) x 60%
= $-10
So the answer is $-10
Answer: The numbers are 10 and 23
Step-by-step explanation:
Let the smaller number be x
And the larger number be y
Ist sentence;
1. The sum of two numbers is 33.
X + y= 33 .........eqn 1
2. second sentence
the larger number is 3 more than two times the smaller number.
Y = 3 +2x
Put y into eqn 1
X+ 3 +2x = 33
3x= 33- 3
3x= 30
X = 30/3
X= 10 and y= 3+ 2x
Y= 3+ 2(10)
Y = 3+ 20
Y= 23
Therefore the two numbers are 10 and 23
Answer:
see below
Step-by-step explanation:
Standard equation for a circle with center h,k and radius r
(x-h)^2 + (y-k)^2 = r^2
so for this one center = (1,2) radius = 4
Greetings from Brasil...
<em />
Here's our problem:
From potentiation properties:
Mᵃ ÷ Mᵇ = Mᵃ⁻ᵇ
<em>division of power of the same base: I repeat the base and subtract the exponents</em>
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Bringing to our problem
12¹⁶ ÷ 12⁴
12¹⁶⁻⁴
<h2>12¹²</h2>
