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alexdok [17]
3 years ago
10

The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a

team member, the inequality 260 ≤ 4h + 28 < 324 , represents the range of heights of the cheerleaders, in inches. Select all possible heights for the University of Central Florida's cheerleaders.
Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

Step-by-step explanation:

we have

260 \leq 4h+28

Divide the compound inequality into two inequalities

260 \leq 4h+28 -----> inequality A

4h+28 -----> inequality B

Solve inequality A

260 \leq 4h+28

Subtract 28 both sides

232 \leq 4h

Divide by 4 both sides

58 \leq h

Rewrite

h \geq 58\ in

Solve the inequality B

4h+28

Subtract 28 both sides

4h

Divide by 4 both sides

h

therefore

The range of heights of the cheerleaders is the interval [58, 74)

All real numbers greater than or equal to 58 inches and less than 74 inches

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3(r+2)+5(2-r) =-32 can someone tell em the answer to that please
Alex17521 [72]

Answer:

r = 24

Step-by-step explanation:

3(r+2)+5(2−r)=−32

Step 1: Simplify both sides of the equation.

3(r+2)+5(2−r)=−32

(3)(r)+(3)(2)+(5)(2)+(5)(−r)=−32(Distribute)

3r+6+10+−5r=−32

(3r+−5r)+(6+10)=−32(Combine Like Terms)

−2r+16=−32

−2r+16=−32

Step 2: Subtract 16 from both sides.

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Step 3: Divide both sides by -2.

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2 years ago
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Solve for x: 2(x 3)2 − 4 = 0 Round your answer to the nearest hundredth. X = 4. 41, 1. 59 x = 1. 34, 5. 24 x = −1. 34, −5. 24 x
gladu [14]

The two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.

The standard form of the quadratic equation is,

ax^2+bx+c=0

Here, (<em>a,b,c</em>) are the real numbers and <em>x </em>is the variable.

To find the value of x, the following formula is used,

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The given equation is,

2(x+ 3)^2 - 4 = 0

To solve this equation, we need to apply some mathematical operations over it. Let's start with opening the brackets.

2(x+ 3)^2 - 4 = 0\\2(x^2+6x+9)-4=0\\2x^2+12x+14-4\\2x^2+12x+12=0\\x^2+6x+7=0

On comparing with standard equation we get,

a=1, b=6, c=7

Put this values in the above formula,

x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=\dfrac{-(6)\pm\sqrt{(6)^2-4(1)(7)}}{2(1)}\\x=-4.41,-1.59

Hence, the two values when the provided quadratic equation is solved for the x are -4.41 and -1.59 to the nearest hundredth.

Learn more about the quadratic equation here;

brainly.com/question/1214333

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