Question

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=11x−3 and CE=12−4x. Find the length of AC.

Answer 1

Answer:

AC=16 units

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.  It was given that diagonals AC and BD intersect at point E.

This implies that: $AE=CE$.

We substitute the expression for x, we get:

$11x-3=12-4x$.

Group similar terms to get:

$11x+4x=12+3$.

$15x=15$.

$x=1$

AC = 2(12-4x)

AC=2(12-4(1))

AC=2(8)

AC=16