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elena-14-01-66 [18.8K]
2 years ago
10

What is the answer to 28r+24

Mathematics
2 answers:
dimulka [17.4K]2 years ago
4 0

Answer:

  • \boxed{\sf{4(7r+6)}}

Step-by-step explanation:

In order to solve this problem, you must find the factor to use the distributive property.

<u>Distributive property:</u>

→ A(B+C)=AB+AC

28r+24

4*7=28

4*6=24

Rewrite the problem down.

4*7r+4*6

Solve.

4*7r=28r

4*6=24

<u>28r+24</u>

  • <u>Therefore, the final answer is 4(7r+6).</u>

I hope this helps! Let me know if you have any questions!

r-ruslan [8.4K]2 years ago
3 0

Answer:

4(7r+6).

Step-by-step explanation:

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2 years ago
X to the third power = 125/27
nika2105 [10]
When raising a fraction to a power, we can raise the numerator and denominator to the power. To find x, we need to find the cube root of both 125 and  27. That is, the numbers that when multiplied by themseelves 3 times result in 125 and 27.

\sqrt[3]{125} = 5

\sqrt[3]{27} =3

So x = \frac{5}{3}
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4 years ago
THERE ARE 1,000 WORKERS IN A FACTORY . EACH WORKER WORKS 30 HOURS A WEEK AND IS PAID $5.50 AN HOUR . HOW MUCH DOES THE COMPANY H
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3 years ago
Read 2 more answers
The area of a rectangle is 105 square units. Its width measures 7 units. Find the length of its diagonal. Round to the nearest t
mezya [45]

Answer:

16.6

Step-by-step explanation:

The rectangle has an area of 105. It's width is 7.

1: Find the length

     \frac{area}{width}=length

     \frac{105}{7}= 15

      Length=15

2: Pythagorean theorem

      a^{2} +b^2=c^2

       7^{2}+15^2=c^2

       49+225=c^2

        275=c^2

         \sqrt{275} = \sqrt{c^2\\}

          16.55≈c

           Rounded to nearest tenth

              16.6

6 0
3 years ago
A group of four components is known to contain two defectives. An inspector tests the components one at a time until the two def
Stells [14]

Answer:

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

Step-by-step explanation:

Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6

Y can only take values of 2, 3 and 4

So, Probability of Y = P(Y) = 1C(Y-1) / 6

when Y = 2, P(2) = 1/6 = 0.167

when Y = 3, P(3) = 2/6 = 0.333

when Y = 4, P(4) = 3/6 = 0.5

4 0
3 years ago
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