Given the quadratic equation, (x + 2)^2 = a.
And, x = 1
Solving for the value of a
(x + 2)^2 = a.
a = (x + 2)^2
a = (1 + 2)^2
a = 3^2
a = 9
The value of a is 9
Just the first one, r is 4x+2, and h is 5x+4, plug them into the formula pls
I think the answer is B not too sure tho bro
Answer:
Your answer is in the screenshot! :)
Step-by-step explanation:
1. Solve for yy in y+7x=50y+7x=50. y=50-7x
y=50−7x
2. Substitute y=50-7xy=50−7x into 14x-5y=-2814x−5y=−28. 49x-250=-28
49x−250=−28
3. Solve for xx in 49x-250=-2849x−250=−28. x=\frac{222}{49}
x= 49 222
4. Substitute x=\frac{222}{49}x= 49 222 into y=50-7xy=50−7x.
y=\frac{128}{7} y= 7 128
5. Therefore, \begin{aligned}&x=\frac{222}{49}\\&y=\frac{128}{7}\end{aligned} x= 49 222 y= 7 128 Hope this helped!! :))