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2 years ago

Suppose that IQ scores have a bell-shaped distribution with a mean of

Mathematics

1 answer:

Svetllana [295]2 years ago

6 0

Answer:

68 %

Step-by-step explanation:

The Empirical rule formula states that:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean of 96 and a Standard deviation of 17

Applying , the first empirical rule for 1 standard deviation from the mean, we have:

μ - σ

96 - 17

= 79

μ + σ

96 + 17

= 113

Therefore, the percentage of IQ scores that are between 79 and 113 is 68%

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Find the area of the figure.<br><br> answer choices:<br> 31 ft², 80 ft², 40 ft², 60 ft²

IrinaVladis [17]

Answer:

60 ft²

Step-by-step explanation:

You can divide the figure into 2 parts.

First, solve for the rectangle: Area of a rectangle = b*h = 4ft x 10ft = 40ft²

Then, solve for the triangle:

Height = 10ft - 5ft = 5ft

Base = 12ft - 4ft = 8ft

Area of a triangle = (b*h)/2 = (5ft x 8ft)/2 = 20ft²

Just add them together: 20ft² + 40ft² = 60ft²

3 0

2 years ago

Drag each tile to the correct box.

kolbaska11 [484]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 unitsb) Distance between points E (-2, -1) and F( -2, -5) is 4 unitsc) Distance between points C (-4, 1) and D( 1, 1) is 5 unitsd) Distance between points G(3, -5) and H(6, -5) is 3 unitsStep-by-step explanation:We need to find the distance between each paira) A (5, 4) and B( 5, -2)

Step-by-step explanation:

8 0

2 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

What is the volume of the rectangular prism.

Pie

Answer:

C: 200

Step-by-step explanation:

Just multiply 12.5 x 8 x 2 to get the answer.

3 0

2 years ago

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How many times larger is 150,00 than 150