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vazorg [7]
3 years ago
8

Which of the following options is not viable in order to solve the following systems of equations?

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

I think B is the correct choice.

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For the figures given
lesya [120]

Step-by-step explanation:

  1. line of symmetry = 0. Rotational symmetry = 120°
  2. line of symmetry = 4. Rotational symmetry = 90°
  3. line of symmetry = 0. Rotational symmetry = 360°
  4. line of symmetry = 0. Rotational symmetry = 180°

hope you are helped.

5 0
3 years ago
During a weekend, the manager of a mall gave away gift cards to every 80th person who visited the mall.
yuradex [85]
What is the question??
3 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
Helga [31]

Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

4 0
3 years ago
Solve for the variable 4/2 = 9/x<br> A x = 2/9 b x=4 C =4.5 D x= 18
Lesechka [4]

Answer:

\frac{4}{2}  =  \frac{9}{x}  \\

perform cross multiplication:

(4 \times x) = 9 \times 2 \\ 4x = 18 \\ → \: { \tt{x = 4.5}}

5 0
3 years ago
HURRY!! 8.1=8w- 17.5. Solve for w​
jasenka [17]
W= 3.2

Need explaining?
5 0
3 years ago
Read 2 more answers
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