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4 years ago

Given that abc=def, m

Mathematics

1 answer:

ikadub [295]4 years ago

4 0

Answer:

ABC. def, m is a brain training site. off work at abc .bac. cab .equal abcdef

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Taffy Twist candy company keeps the same ratio of pieces of strawberry candies to Banana candies in their packs the mega pack ha

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

grigory [225]

Answer:

Tt = Ts + Ce^-kt

Tt = 62 + 138e^-0.0068t

Step-by-step explanation:

The initial value problem for the Newton cooling rate is :

Tt = Ts + Ce^-kt

Initial temperature,when freshly poured Ti = 200°F

Temperature after 11 minutes = 190°F

Temperature of room, Ts= 62°F

Using the relation :

Tt = Ts + Ce^-kt

Temperature after time, t

When freshly poured, t = 0

k = constant of proportionality

We can then solve for C and k as follows :

200 = 62 + Ce^-0k

200 = 62 + C

C = 200 - 62 = 138°F

Using the Temperature after 11 minutes ; we can find, k, proportionality constant:

Temperature, Tt after, t = 11 minutes = 190

Tt = Ts + Ce^-kt

190 = 62 + 138e^-11k

128 = 138e^-11k

128 / 138 = e^-11k

0.9275 = e^-11k

Take In of both sides :

−0.075223 = - 11k

k = −0.075223 / - 11

k = 0.0068

The model function becomes :

Ts = 62 ; C = 138

Tt = 62 + 138e^-0.0068t

3 0

3 years ago

Write the standard form of the equation of each line given the slope and y-intereept.

Elena-2011 [213]

Answer:

5y + 15x = 25, 9x - y = -4

Step-by-step explanation:

The standard form is Ax + By = C. We can make this simple by first creating the slope intercept equations of both questions:

1. y = (-3/5)x + 5

2. y = 9x + 4

For the first one, we must first get rid of the denominator by multiplying everything by 5, so we get 5y = -15x + 25, and then you can add 3x to both sides to arrive at your first standard eqn, 5y + 15x = 25.

For the second, all you need to do is swap the y and the 4, subtracting both y and 4 from each side, arriving at 9x - y = -4

6 0

3 years ago

Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900

rosijanka [135]

Answer:

The 33 week gestation period baby has a zscore of -0.47.

The 41 week gestation period baby has a zscore of -0.94.

The 41 week gestation period baby weighs less relative to the gestation period.

Step-by-step explanation:

Normal model problems can be solved by the zscore formula.

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

The zscore represents how many standard deviations the value of X is above or below the mean $\mu$ . This means that the baby with the lowest Zscore is the one who weighs relatively less to the gestation period.

33 week gestation period baby:

Babies born after a gestation period of 32 to 35 weeks have a mean weight of 2700 grams and a standard deviation of 900 grams, so $\mu = 2700, \sigma = 900$ .

A 33-week gestation period baby weighs 2275 grams. So $X = 2275$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2275 - 2700}{900}$

$Z = -0.47$

41 week gestation period baby:

Babies born after a gestation period of 40 weeks have a mean weight of 3200 grams and a standard deviation of 450 grams, so $\mu = 3200, \sigma = 450$