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alexira [117]
3 years ago
14

Numa turma, 5% dos homens e 2% das mulheres tem mais de 1,60m de altura. Por outro lado, 60% dos estudantes são homens. Se um es

tudante é selecionado aleatoriamente e tem mais de 1,60m de altura, qual a probabilidade de que o estudantes seja mulher?
Mathematics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

0.8%

Step-by-step explanation:

Because they are two independent events, the final probability is the product of the probability of each event.

First event:

The complement of a student being male is that he is female.

Therefore, if 60% is male, the remaining 100% is 40%, meaning that 40% of the students are female.

Second event:

If she's taller than 5'4", we're told she has a 2% chance of being a woman.

Therefore the final probability is:

0.4*0.02 = 0.008

That is, the probability that it is female and that it is over 1.6 meters tall is 0.8%.

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Answer:

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Let profit be x

to find profit use formula,

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20*$9000=100x

$180000/100=x

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cost price +profit

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$91800

therefore selling price of a table is $91800

Step-by-step explanation:

Hope this helps u!!

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Add <span /><span><span><span><span><span><span>12</span></span><span /></span></span><span /></span><span>12</span></span> to both sides
<span /><span><span><span><span><span><span>8</span><span>x</span><span>=</span><span>5</span><span>x</span><span>+</span><span>15</span><span>+</span><span>12</span></span><span /></span></span><span /></span><span>8x=5x+15+12</span></span>
2<span> </span>Simplify <span /><span><span><span><span><span><span>5</span><span>x</span><span>+</span><span>15</span><span>+</span><span>12</span></span><span /></span></span><span /></span><span>5x+15+12</span></span> to <span /><span><span><span><span><span><span>5</span><span>x</span><span>+</span><span>27</span></span><span /></span></span><span /></span><span>5x+27</span></span>
<span /><span><span><span><span><span><span>8</span><span>x</span><span>=</span><span>5</span><span>x</span><span>+</span><span>27</span></span><span /></span></span><span /></span><span>8x=5x+27</span></span>
3<span> </span>Subtract <span /><span><span><span><span><span><span>5</span><span>x</span></span><span /></span></span><span /></span><span>5x</span></span> from both sides
<span /><span><span><span><span><span><span>8</span><span>x</span><span>−</span><span>5</span><span>x</span><span>=</span><span>27</span></span><span /></span></span><span /></span><span>8x−5x=27</span></span>
4<span> </span>Simplify <span /><span><span><span><span><span><span>8</span><span>x</span><span>−</span><span>5</span><span>x</span></span><span /></span></span><span /></span><span>8x−5x</span></span> to <span /><span><span><span><span><span><span>3</span><span>x</span></span><span /></span></span><span /></span><span>3x</span></span>
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5 0
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