Alright so the first one involves in shading.
You can see that Jack and Renee have two bars with rectangles inside the bar.
Jack took 3/4 hours or in words, three out of four. So in Jack's bar, shade 3 boxes and leave one unshaded.
Renee took 2/3 or two out of three. Shade 2 boxes in Renee's bar and see the difference.
As you can see, Jack has more shade length than Renee and that could only mean one thing:
Jack took longer to fix the tire than Renee.
The symbol that represents this is 3/4 > 2/3
The second activity has the same case.
Water: 3/5 means that you have to shade three boxes and leave the other two unshaded.
Sports Drink: 4/6 means that you have to shade four boxes and leave the other two unshaded.
As you can see again, there is more sports drink than the water since the shade length is longer in the sports drink than on the water.
This meant that she poured in more sports drink than water.
The third activity is just as simple, you just need to visually make up your own sections. Do the shading then see which one is bigger then just input the sign (hint: the first one is < and the second one is >)
cheers
Answer:
9.5 inches per month
Step-by-step explanation:
Given the information about the depth of the pond:
Month 1: 93 in
Month 2: 98 in
Month 3: 112 in
From month 1 to month 3, the average rate of change of the depth of the pond, in inches per month can be calculated using formula
Hence, from month 1 to month 3, what is the average rate of change of the depth of the pond, in inches per month is
All you have to do is x times 42 plus y times 42 and then you have to add the first day on which is 89.This is how it should look (x*42)+(y*42)+89.
Step-by-step explanation:
g(x) = 3x - 2
g(-4) = 3(-4) - 2
= -12 -2
= -14
Answer:
{GT, GH, BT, BH, RT, RH};
1 /5;
Mutually exclusive ;
Not mutually exclusive.
Step-by-step explanation:
Given :
Green cards, G = 4
Blue cards, B = 4
Red cards, R = 2
For a coin toss :
{H, T}
A card is picked, then a coin is tossed :
Sample space :
{GT, GH, BT, BH, RT, RH}
2.) probability of picking a green card, then probability of landing a head on a coin toss
P(A) = number of required outcome / Total possible outcomes
P(A) = P(green card) * P(Head)
P(A) = (4 / 10) * (1/2)
P(A) = 4 /20
P(A) = 1/5
C.)
Both A and B are mutually exclusive, since both event A and event B cannot occur together, since both red and green cannot be picked during a single pick, this either a red is picked or green is picked, then they are A and B are mutually exclusive.
D.) Event A and C are not mutually exclusive, picking a green card, event A and picking a red or blue card, event B. Both event can happen simultaneously, hence, event A and B are not mutually exclusive.
