Answer:
Graph 1: u-v
Graph 2: u-w
Graph 3: w-v
Graph 4: v-u
Step-by-step explanation:
First, let us find u-v, u-w, w-v, v-u.
<u>u-v:</u>
<-2,-7> - <3,-4> = <-2-3,-7-(-4)>= <-5,-3>
<u>u-w:</u>
<-2,-7> - <5,1> = <-2-5,-7-1> = <-7,-8>
<u>w-v:</u>
<5,1> - <3,-4> = <5-3,1-(-4)> = <2,5>
<u>v-u:</u>
<3,-4> - <-2,-7> = <3-(-2),-4-(-7)> = <5,3>
Then we can match the results with the graphs.
Graph 1: u-v
Graph 2: u-w
Graph 3: w-v
Graph 4: v-u
1. rational 2. irrational 3. irrational 4. rational
Answer:
Choice A is correct
Step-by-step explanation:
The distribution for town A is symmetric, but the distribution for town B is negatively skewed. From the box plots it is clear that the tails of the box plot for town A are equal in length while for town B the left tail is longer implying a negatively skewed distribution.
Answer:
the answer is 8 7/8
Step-by-step explanation:
Recall the definition of the cross product:
i x i = j x j = k x k = 0
i x j = k
j x k = i
k x i = j
The cross product is antisymmetric, or anticommutative, meaning that for any vectors u and v, we have u x v = - (v x u).
It's also distributive, so for any vectors u, v, and w, we have (u + v) x w = (u x w) + (v x w).
Taking all of these properties together, we get
b x a = (6i - j + 2k) x (2i + 2j - 5k)
b x a = 12 (i x i) - 2 (j x i) + 4 (k x i)
............. + 12 (i x j) - 2 (j x j) + 4 (k x j)
............. - 30 (i x k) + 5 (j x k) - 10 (k x k)
b x a = 1 (j x k) + 34 (k x i) + 14 (i x j)
b x a = i + 34j + 14k
