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Anna [14]
3 years ago
14

Write the equation for the line in slope intercept form

Mathematics
1 answer:
lianna [129]3 years ago
3 0

Answer:

y = -x + 5

Step-by-step explanation:

lmk if you want an explanation

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Find two consecutive even numbers whose sum is 126
aalyn [17]

Answer:

62+64 = 126

Step-by-step explanation:

If 126/2=63, then 62+64 = 126

3 0
3 years ago
Read 2 more answers
Translate the phrase into a numerical expression of One hundred divided by the quantity three times five
dimulka [17.4K]
\frac{100}{3*5}
4 0
4 years ago
2x + y = 3
Leto [7]
It should be B 3y=5 hope I'm right.
3 0
3 years ago
The display provided from technology available below results from using data for a smartphone​ carrier's data speeds at airports
german

Answer:

The null and alternative hypothesis are:

H_0: \mu=5\\\\H_a:\mu< 5

Test statistic t=-0.256

P-value = 0.4

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Sample mean (M): 4.79</em>

<em>Sample STD (s): 5.8</em>

<em>Sample size (n): 50</em>

This is a hypothesis test for the population mean.

The claim is that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Then, the null and alternative hypothesis are:

H_0: \mu=5\\\\H_a:\mu< 5

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=4.79.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=5.8.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.8}{\sqrt{50}}=0.82

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.79-5}{0.82}=\dfrac{-0.21}{0.82}=-0.256

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a left-tailed test, with 49 degrees of freedom and t=-0.256, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.4) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

5 0
3 years ago
**CORRECT** answer will get brainliest
hammer [34]

Answer:

B

Step-by-step explanation:

{1,2,3,4,5,6, skip}; P(1)=0.125

6 0
3 years ago
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