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3 years ago

What is the Sea level

Mathematics

2 answers:

Elena L [17]3 years ago

6 0

The level of the sea's surface, used in reckoning the height of things such as hills and as a barometric standard.

If you are looking for the exact height of the sea just google it it's different all over the world.

Hope that's what you're looking for.

eimsori [14]3 years ago

6 0

It depends what Sea also you can search it up

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Ms.Malone received $3.40 in change. What is the amount as a fraction in simplest terms.

sammy [17]

To write 3.40 as a fraction you have to write 3.40 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.
3.40 = 3.40/1 = 34/10

And finally we have:
3.40 as a fraction equals 34/10 simplified we get: 3 2/5

3 0

3 years ago

It has been reported that men are more likely than women to participate in online auctions. In a recent survey, 65% of responde

vivado [14]

Answer:

0.84 or 84%

Step-by-step explanation:

Let 'n' be number of people who took the survey, the number of men who answered the survey is 0.45n. The number of men who answered the survey and have participated in online auctions is 0.38n. Therefore, choosing from the population of men who took the survey (0.45n) the probability that a respondent had participated in an online auction is:

$P =\frac{0.38n}{0.45n}\\P=0.84$

8 0

3 years ago

PLS HELP WILL GIVE BRAINLIEST

Oduvanchick [21]

Answer:

The angle acute so my guess is 60

Hope this helps :)

6 0

3 years ago

PLEASE HELP I AM DESPERATE I WILL GIVE THANKS, 5 STARS, AND THE BRAINLIEST!!!

Amanda [17]

g(-2) + g(2) = 22

Step-by-step explanation:

For x = -2, g(x) = x^2 - 3x

g(-2) = (-2)^2 - 3(-2) = 4 + 6 = 10

For x = 2, g(x) = 12, therefore

g(-2) + g(2) = 10 + 12 = 22

3 0

3 years ago

If the expression (3^(d)*\sqrt(5))/(3^(2)*\sqrt(45)) is equal to 3, what is the value of d

Digiron [165]

$3^d\cdot\dfrac{\sqrt5}{3^2\cdot\sqrt{45}}=3\\\\\dfrac{3^d\sqrt5}{3^2\sqrt{9\cdot5}}=3\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\dfrac{3^d\sqrt5}{3^2\sqrt9\cdot\sqrt5}=3\\\\\dfrac{3^d}{3^2\cdot3}=3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{3^d}{3^{2+1}}=3\\\\\dfrac{3^d}{3^3}=3\qquad\text{multiply both sides by}\ 3^3\\\\3^d=3\cdot3^3\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\3^d=3^{1+3}\\\\3^d=3^4\iff\boxed{d=4}$

8 0

3 years ago