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tino4ka555 [31]
3 years ago
6

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

exactly 3 inches?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
The volume of the metal box if the box was completely solid (V1), is:
 
 V1=(12 inches)³
 V1=1728 inches³
 
 As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:
 
 W=12 inches-(3 inchesx2)
 W=6 inches
 
 Then, the volumen of the no solid metal box is:
 
 V2=(6 inches)³
 V2= 216 inches³
 
 Therefore, the volume of metal needed to smelt the cubical metal box, is:
 
 V3=V1-V2
 V3=1728 inches³-216 inches³
 V3=1512 inches³
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Step-by-step explanation:

<u>Statements:</u>                                                        <u>Reasons:</u>

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6)\text{ } PQ=2XQ                                                      Substitution

7)\text{ } QY=YR                                                        Definition of Midpoint

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12)\text{ }  XQ=PX=QY=YR                                Transitive Property

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15)\text{ } RP=2RZ                                                     Substitution

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The fraction to the left would be n over 80. the denominator (the number on the bottom) would be the whole amount. n would be the unknown number

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