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tino4ka555 [31]
3 years ago
6

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

exactly 3 inches?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
The volume of the metal box if the box was completely solid (V1), is:
 
 V1=(12 inches)³
 V1=1728 inches³
 
 As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:
 
 W=12 inches-(3 inchesx2)
 W=6 inches
 
 Then, the volumen of the no solid metal box is:
 
 V2=(6 inches)³
 V2= 216 inches³
 
 Therefore, the volume of metal needed to smelt the cubical metal box, is:
 
 V3=V1-V2
 V3=1728 inches³-216 inches³
 V3=1512 inches³
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<h3>How to form mathematical expression from the given description?</h3>

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For the given case, the terms were 27x and 6x and the expression formed from them is 27x+6x

This means both the terms were added together, as denoted by '+' (called 'plus') sign.

When two terms are written with 'plus' sign in between, then that means they're added to each other and the result will be addition of both of their's values.

Thus, the mathematical word describing  both 27x and 6x in the expression 27x+6x is <u><em>addition</em></u>"

Learn more about addition here:

brainly.com/question/14148883

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