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tino4ka555 [31]
3 years ago
6

20 how much metal is needed to smelt a cubical metal box with outer side 12 inches long if the thickness of its walls should be

exactly 3 inches?
Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
The volume of the metal box if the box was completely solid (V1), is:
 
 V1=(12 inches)³
 V1=1728 inches³
 
 As there are 3 inches of metal on both sides, the widht if the metal box was not completely solid, is:
 
 W=12 inches-(3 inchesx2)
 W=6 inches
 
 Then, the volumen of the no solid metal box is:
 
 V2=(6 inches)³
 V2= 216 inches³
 
 Therefore, the volume of metal needed to smelt the cubical metal box, is:
 
 V3=V1-V2
 V3=1728 inches³-216 inches³
 V3=1512 inches³
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Write the explicit formula that represents the geometric sequence -2, 8, -32, 128
MissTica
So hmm the first term is -2

and if we divide one term by the term before it, we'd get the "common ratio" "r"

so hmm say -32/8 that gives us -4, so r = -4

thus \bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1r^{n-1}\qquad 
\begin{cases}
a_1=\textit{first term}\\
r=\textit{common ratio}\\
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a_1=-2\\
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3 years ago
Any help will be great!
son4ous [18]

Answer:

180

Step-by-step explanation:

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3 years ago
Read 2 more answers
Which number is a factor of 12 but not a multiple of 3?
Delvig [45]
First list all the factors of 12;

1, 2, 3, 4, 6, 12

now let's see which ones are multiples of 3;

3, 6, 12 

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6 0
3 years ago
There are 7 acts in a talent show.
lara31 [8.8K]

Answer:

<u><em></em></u>

  • <u><em>Event A: 1/35</em></u>
  • <u><em>Event B: 1/840</em></u>

<u><em></em></u>

Explanation:

<u>Event A</u>

For the event A, the order of the first 4 acts does not matter.

The number of different four acts taken from a set of seven acts, when the order does not matter, is calculated using the concept of combinations.

Thus, the number of ways that the first <em>four acts</em> can be scheduled is:

          C(m,n)=\dfrac{m!}{n!(m-n)!}

         C(7,4)=\dfrac{7!}{4!(7-4)!}=\dfrac{7!}{4!(3)!}=35

And<em> the number of ways that four acts is the singer, the juggler, the guitarist, and the violinist, in any order</em>, is 1: C(4,4).

Therefore the<em> probability of Event A</em> is:

           P(A)=1/35

Event B

Now the order matters. The difference between combinations and permutations is ordering. When the order matters you need to use permutations.

The number of ways in which <em>four acts </em>can be scheculed when the order matters is:

           P(m,n)=\dfrac{m!}{(m-n)!}

         P(m,n)=\dfrac{7!}{(7-4)!}=P(m,n)=\dfrac{7!}{4!}=840

The number of ways <em>the comedian is first, the guitarist is second, the dancer is third, and the juggler is fourth</em> is 1: P(4,4)

Therefore, <em>the probability of Event B</em> is:

            P(B)=1/840

7 0
3 years ago
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