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givi [52]
3 years ago
13

What are the solutions to g(x)=7x^2=567

Mathematics
2 answers:
ryzh [129]3 years ago
7 0

The solution of the given equation is +9 and -9.

Step-by-step explanation:

Given,

g(x) = 7x^{2} =567

To find the solution of x.

7x^{2} = 567

or, x^{2} =\frac{567}{7}

or, x^{2} = 81

or, x = ±\sqrt{81} [ square roots has two values so we put ±]

or, x = ±9

qwelly [4]3 years ago
3 0

Answer:

x = ±9

Step-by-step explanation:

7x^2=567

Divide each side by 7

7/7x^2=567/7

x^2 =81

Take the square root of each side

sqrt(x^2) = sqrt(81)

x = ±9

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Komok [63]

Answer:

The other two angles are 75° and 125°.

Step-by-step explanation:

Let three angles are 2x, 3x and 5x.

The smallest angle is 50.

It means,

2x = 50

x = 25

So,

3x = 3(25) = 75°

5x = 5(25) = 125°

So, the other two angles are 75° and 125°.

5 0
3 years ago
105 students in 3 Classes
podryga [215]

Answer:

35

Step-by-step explanation:

just divide em

8 0
2 years ago
Find the value of p for which x = -2, y = -1 is a solution of linear equation 5x + 2py = 2p.​
Rom4ik [11]
I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)


I don’t know if I’m right but yea...



8 0
3 years ago
Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?
xxTIMURxx [149]

Answer:

x² + y² = 34

Formula:

  • (x - h)² + (y - k)² = r²                    where (h, k) is the center

<u>Here find the radius using distance formula</u>:                → origin : (0, 0)

  • √(x2-x1)²+(y2-y1)²
  • √(3-0)²+(5-0)²
  • √9+25
  • √34

<u>Thus the equation of circle</u>:

  • (x - 0)² + (y - 0)² = (√34)²
  • (x - 0)² + (y - 0)² = 34
  • x² + y² = 34

7 0
3 years ago
Read 2 more answers
Please help math problem
dedylja [7]

Answer :im not very sureeee

Step-by-step explanation:

8 0
3 years ago
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