Answer:
411.88 N
Explanation:
Given that:
mass of satellite m = 1847 kg
mass of the earth M = 5.97 × 10²⁴ kg
centripetal acceleration a = 0.223 m/s²
The magnitude of the force exerted by the earth on the satellite = the centripetal force that is being exerted by the satellite.
∴
Answer: 45.3°
Explanation:
Given,
Length of ladder = l
Weight of ladder = w
Coefficient of friction = μs = 0.495
Smallest angle the ladder makes = θ
If we assume the forces in the vertical direction to be N1, and the forces in the horizontal direction to be N2, then,
N1 = mg and
N2 = μmg
Moment at a point A in the clockwise direction is
N2 Lsinθ - mg.(L/2).cosθ = 0
μmgLsinθ - mg.(L/2).cosθ = 0
μmgLsinθ = mg.(L/2).cosθ
μsinθ = cosθ/2
sin θ / cos θ = 1 / 2μ
Tan θ = 1 / 2μ
Substituting the value of μ = 0.495, we have
Tan θ = 1 / 2 * 0.495
Tan θ = 1 / 0.99
Tan θ = 1.01
θ = tan^-1(1.01)
θ = 45.3°
The coefficient of linear expansion is
<em>(change of length, feet) / (original length, feet)</em> per °F.
Since the numerator and denominator of the fraction have the same
unit, the coefficient turns out to be just a number, with no unit.
The answer is P-waves and S-waves
Electrons must be excited
