Question

Write the ratios for sin A and cos A. The triangle is not drawn to scale

Answer 1

Answer:

$sin(A)=\frac{48}{50}$, $cos(A)=\frac{14}{50}$

Step-by-step explanation:

Part a) Find the sin(A)

we know that

In the right triangle ABC

$sin(A)=\frac{BC}{AB}$ ----> the sine of angle (A)  is the opposite side angle (A) divided by the hypotenuse

substitute the values

$sin(A)=\frac{48}{50}$

Part b) Find the cos(A)

we know that

In the right triangle ABC

$cos(A)=\frac{AC}{AB}$ ----> the cosine of angle (A)  is the adjacent side angle (A) divided by the hypotenuse

substitute the values

$cos(A)=\frac{14}{50}$