Answer:
To find critical points, take the first derivative and set it equal to zero:
f(x) = -2x^2 + 4x + 5
f'(x) = -4x + 4
-4x+4 = 0
-4x = -4
x = 1
Critical point at x = 1
Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.
Answer:
18
Step-by-step explanation:
10 +3 =13 +5 =18
so that is how you get the answer 18 it's simple really
The answer is 5. Hope that helps :)
