All categories

3 years ago

HELPPPPPPP ME PLEASEE

Mathematics

2 answers:

Tcecarenko [31]3 years ago

7 0

Answer:

Step-by-step explanation:

180 - 135= 45

Svetlanka [38]3 years ago

5 0

Answer:

Step-by-step explanation:

Since they are consecutive angles

You would subtract 180 from 135 to get 45 Measure 2 is 45

You might be interested in

) Turner helped his grandfather build a raised garden bed for Turner's grandmother. The

worty [1.4K]

The length of the garden bed is 6 feet

<h3>The volume of a rectangular prism</h3>

The formula for calculating the volume of a rectangular prism is expressed as:

V = lwh

If turner and his grandfather used 18 bags of topsoil, each containing 3/4 of a cubic foot, to fill the bed completely, hence;

V = 3/4 * 18

V = 13.5 cubic foot

In order to determine the length of the garden;

135/10 = 9/2 * 1/2l

27/2 =9/4 l

18l = 27 * 4

18l = 108

l = 6 feet

Hence the length of the garden bed is 6 feet

Learn more on volume of rectangular prism here: brainly.com/question/24284033

5 0

2 years ago

Use the fundamental theorem of calculus to find the area of the region between the graph of the function x^5 + 8x^4 + 2x^2 + 5x

BaLLatris [955]

Answer:

The area of the region is 25,351 $units^2$ .

Step-by-step explanation:

The Fundamental Theorem of Calculus: if $f$ is a continuous function on $[a,b]$ , then

$\int_{a}^{b} f(x)dx = F(b) - F(a) = F(x) | {_a^b}$

where $F$ is an antiderivative of $f$ .

A function $F$ is an antiderivative of the function $f$ if

$F^{'}(x)=f(x)$

The theorem relates differential and integral calculus, and tells us how we can find the area under a curve using antidifferentiation.

To find the area of the region between the graph of the function $x^5 + 8x^4 + 2x^2 + 5x + 15$ and the x-axis on the interval [-6, 6] you must:

Apply the Fundamental Theorem of Calculus

$\int _{-6}^6(x^5+8x^4+2x^2+5x+15)dx$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\\\\int _{-6}^6x^5dx+\int _{-6}^68x^4dx+\int _{-6}^62x^2dx+\int _{-6}^65xdx+\int _{-6}^615dx$

$\int _{-6}^6x^5dx=0\\\\\int _{-6}^68x^4dx=\frac{124416}{5}\\\\\int _{-6}^62x^2dx=288\\\\\int _{-6}^65xdx=0\\\\\int _{-6}^615dx=180\\\\0+\frac{124416}{5}+288+0+18\\\\\frac{126756}{5}\approx 25351.2$