Answer:
The answer is C. 450
Step-by-step explanation:
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Next Question
Correct
The best estimate for the lizard population is 450.
marked lizards counted
total lizards counted
=
total marked lizards
estimated lizard population
→
16
200
=
36
p
→ p = 450
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
</span>
Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
Step-by-step explanation:
1+2√2 ²π = 9+4√2 π cm² thats my answer
Answer:
x = 5
Step-by-step explanation:
The 2 strokes through XM and MY indicate the segments are congruent, so
YM = MX , that is
8x - 24 = 3x + 1 ( subtract 3x from both sides )
5x - 24 = 1 ( add 24 to both sides )
5x = 25 ( divide both sides by 5 )
x = 5
<h3>
Answer:</h3>
C. 4(x-3)-x
<h3>
Step-by-step explanation:</h3>
All of the given expressions are equivalent to 3x+12 except selection C. Using that in your equation makes it be ...
... 3(x +1) +9 = 4(x -3) -x
... 3x +12 = 3x -12
... 12 = -12 . . . . . <em>false</em>
There is no value of x that will make this true, hence NO SOLUTION.
_____
<em>Comment on the other choices</em>
3x+12 = 3x+12 has an <em>infinite number of solutions</em>, as <u><em>any</em></u> value of x will make this true.
