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Andreyy89
2 years ago
7

How do you separate the number 40 into three parts so that the second number is twice the first number and the third number is t

he same as first number
Mathematics
1 answer:
vampirchik [111]2 years ago
6 0

Hey there mate ;)

<h3><u>Answer:- ( 10 </u><u> </u><u> </u><u> 20</u><u> </u><u> </u><u> 10)</u></h3>

Explanation:-

As per question, we can solve by splitting 40 into :-

10 \:  \:  \: \:  20 \:  \: \:  \:  10

Proof:

● As its told that the second number must be twice the first number , which means 20 should be the double of 10 (Proved)

● Next it is told that the third number must be the same as first number, which means that 10 must be equal to 10, which is true.

So, the answer is <u>(10 20 10)</u>

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Answer:

144 un^2

Step-by-step explanation:

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Top face: 5 × 11 = 55

Triangular faces: 3 × 4 = 12

Add: 44 + 33 + 55 + 12 = 144

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lawyer [7]

Answer:

A) Lexi is 15 and Tanner is 18

B) Enrique has 24 magnets and Peter has 88 magnets

Step-by-step explanation:

1.

t = 3 + l

t + l = 33

substitute:

(t) + l = 33

(3 + l) + l = 33

3 + 2l = 33

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2.

e = p - 64

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substitute

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telo118 [61]

Answer:

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