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aivan3 [116]
3 years ago
7

Rutherford investigated atoms by firing small, positively charged particles at a thin sheet of gold foil. What results would he

expect to see if he believed Thomson’s model of the atom to be correct?
Chemistry
1 answer:
Bezzdna [24]3 years ago
6 0
If Thomson’s model of the atom were correct, Rutherford should have seen a complete reflection of those particles when fired at the foil. Those particles would have hit a solid object (Thomson model) and would have been reflected back at the emitter. However, Rutherford discovered that most of those particles passed through the sheet, either continuing straight through or having the angle change a small amount (bouncing off the nucleus). Only a small number of the particles were reflected back, having hit the nucleus straight on. This led him to believe that there was a small, dense portion of the atom that resided within a larger, emptier space.
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Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

3 0
3 years ago
HELP ME ASAP
gtnhenbr [62]

Answer:D

Explanation:

7 0
2 years ago
Part a draw the major organic product formed when the compound shown below undergoes a reaction with an excess of etoh under aci
sweet-ann [11.9K]
An aldehyde is an organic compound containing a terminal carbonyl group (C = O). This functional group, consisting of a carbon atom bound to a hydrogen atom and an oxygen atom via double bond (the general formula: CHO) is called the aldehyde group. In a reaction of the addition of alcohol to the carbonyl group, it forms hemiacetals. 
On the picture attached it is shown the reaction of alcohol addition to the carbonyl group with the major organic product <span>formed in the reaction.</span>

7 0
2 years ago
What is one way water moves through the nonliving parts of an ecosystem during the water system?
tatyana61 [14]

Answer:

Water moves through the help of living organisms in an ecosystem. ... Plants absorbs water through their root system and loss by transpiration. Water also moves through the living organisms in an ecosystem. Other nonliving processes such as evaporation, precipitation, water returns back into the atmosphere.

Explanation:

hope this helps you

5 0
2 years ago
Read 2 more answers
Help please
Mars2501 [29]

Answer:

electron cloud charge of manganese=-5

Explanation:

atomic number=number of elecron +neutron number

DATA

Neutron NO.=30

atomic NO.=25

e=?

A=e+n

25=e+30

e=25-30

e= -5

6 0
2 years ago
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