Answer:
If you left your aqueous sodium sulfite solution open on the side, atmospheric oxygen would cause the chemical change, the water would hydrate the new compound and the slow evaporation of water would give you lovely large crystals of Na2SO4 without you having to do anything!
Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>
<span>Chemical reaction
(dissociation) of silver oxalate in water:
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.
[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.
x = ∛1.0·10⁻¹¹ ÷ 4.
x = 1.4·10⁻⁴ M.
Answer:
the positively charged particle found in atomic nuclel
Explanation:
protons carry positive charge and attracts negatively charged particles called electron
<span>Given mass: 3.810 g of h2o and 13.96 g of co2.
Mass of CO2 : 13.96 g
moles of CO2 : 0.317 moles / 44.0098
moles of C : 0.317 moles
Mass of water = 3.81 g
moles of water = 0.212 moles / 18.015
moles of H = 0.423 moles X2
Hence the molar ratio C : H is 0.317 : 0.423
= 1.000 : 1.334
Multiplying by 3 on both ratios we get: 3.000 : 4.003
Therefore the empirical formula is C3H4</span>