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dsp73
3 years ago
6

Which best describes ionic compound formulas?

Chemistry
2 answers:
Leokris [45]3 years ago
8 0

Answer:

they have an equal number of positive and negative charges

Vedmedyk [2.9K]3 years ago
6 0

Answer:

They have an equal number of positive and negative charges.

Explanation:

The person above me is correct, plz thank him, not me

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What is true when a reaction has reached equilibrium?
ASHA 777 [7]

Answer:

I think its `b

Explanation:

6 0
3 years ago
Read 2 more answers
Given the following balanced equation at 120°C: A(g) + B(g) ⇋ 2 C(g) + D(s)(a) At equilibrium a 4.0 liter container was found to
BlackZzzverrR [31]

Answer:

a) kc = 0,25

b) [A] = 0,41 M

c) [A] = <em>0,8 M</em>

[B] =<em>0,2 M</em>

[C] = <em>0,2M</em>

Explanation:

The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.

Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.

If global reaction is:

A(g) + B(g) ⇋ 2 C(g) + D(s)

The kc = \frac{[C]^2}{[A][B]}

a) The concentrations of each compound are:

[A] = \frac{1,60 moles}{4,0 L} = <em>0,4 M</em>

[B] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

[C] = \frac{0,40 moles}{4,0 L} = <em>0,1 M</em>

<em>kc = </em>\frac{[0,1]^2}{[0,4][0,1]} = 0,25

b) The addition of B and D in the same amount will, in equilibrium, produce these changes:

[A] = \frac{1,60-x moles}{4,0 L}

[B] = \frac{0,60-x moles}{4,0 L}

[C] = \frac{0,60+2x moles}{4,0 L}

0,25 = \frac{[0,60+2x]^2}{[1,60-x][0,60-x]}

You will obtain

3,75x² +2,95x +0,12 = 0

Solving

x =-0,74363479081119   → No physical sense

x =-0,043031875855476

Thus, concentration of A is:

\frac{1,60-(-0,04 moles)}{4,0 L} = <em>0,41 M</em>

c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:

[A] = \frac{1,60 moles}{2,0 L} = <em>0,8 M</em>

[B] = \frac{0,40 moles}{2,0 L} = <em>0,2 M</em>

[C] = \frac{0,40 moles}{2,0 L} = <em>0,2M</em>

I hope it helps!

8 0
4 years ago
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How do chemical weathering and the formation of biochemical sediment remove carbon from the atmosphere and store it in the geosp
Sav [38]
The chemical weathering process of carbonation removes carbon from the atmosphere. In this process, carbon dioxide in the atmosphere mixes with rainfall to form carbonic acid. This acid then reacts with calcium carbonate or limestone to form calcium bicarbonate. This reaction removes carbon from the atmosphere. Organisms such as corals can remove dissolved carbon from oceans to form their hard rocky structures. Carbon dioxide from the atmosphere is dissolved in ocean water. Overtime they become limestone rock. 
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Water freezes at _____. <br> A. 273°C<br> B. -273°C <br> C. 273 K<br> D. -273 K
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Correct answer is A
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3 years ago
Does the density of an object depend on its size? Explain?.
evablogger [386]

No, the density of an object does not depend on its size.

A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 27 g/10 cm³ = 2.7 g/cm³

A piece of the same type of glass with a volume of 20 cm³ will have a mass

of 54 g. Its density is  

<em>D</em> = <em>m</em>/<em>V</em> = 54 g/20 cm³ = 2.7 g/cm³

Thus, density does not change with the size of an object. Density is an <em>intensive property</em>.

3 0
3 years ago
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