Answer:
a) kc = 0,25
b) [A] = 0,41 M
c) [A] = <em>0,8 M</em>
[B] =<em>0,2 M</em>
[C] = <em>0,2M</em>
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium.
If global reaction is:
A(g) + B(g) ⇋ 2 C(g) + D(s)
The kc = ![\frac{[C]^2}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5E2%7D%7B%5BA%5D%5BB%5D%7D)
a) The concentrations of each compound are:
[A] =
= <em>0,4 M</em>
[B] =
= <em>0,1 M</em>
[C] =
= <em>0,1 M</em>
<em>kc = </em>
= 0,25
b) The addition of B and D in the same amount will, in equilibrium, produce these changes:
[A] =
[B] =
[C] = 
0,25 = ![\frac{[0,60+2x]^2}{[1,60-x][0,60-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C60%2B2x%5D%5E2%7D%7B%5B1%2C60-x%5D%5B0%2C60-x%5D%7D)
You will obtain
3,75x² +2,95x +0,12 = 0
Solving
x =-0,74363479081119 → No physical sense
x =-0,043031875855476
Thus, concentration of A is:
= <em>0,41 M</em>
c) When volume is suddenly halved concentrations will be the concentrations in equilibrium over 2L:
[A] =
= <em>0,8 M</em>
[B] =
= <em>0,2 M</em>
[C] =
= <em>0,2M</em>
I hope it helps!
The chemical weathering process of carbonation removes carbon from the atmosphere. In this process, carbon dioxide in the atmosphere mixes with rainfall to form carbonic acid. This acid then reacts with calcium carbonate or limestone to form calcium bicarbonate. This reaction removes carbon from the atmosphere. Organisms such as corals can remove dissolved carbon from oceans to form their hard rocky structures. Carbon dioxide from the atmosphere is dissolved in ocean water. Overtime they become limestone rock.
No, the density of an object does not depend on its size.
A piece of glass with a volume of 10 cm³ may have a mass of 27 g. Its density is
<em>D</em> = <em>m</em>/<em>V</em> = 27 g/10 cm³ = 2.7 g/cm³
A piece of the same type of glass with a volume of 20 cm³ will have a mass
of 54 g. Its density is
<em>D</em> = <em>m</em>/<em>V</em> = 54 g/20 cm³ = 2.7 g/cm³
Thus, density does not change with the size of an object. Density is an <em>intensive property</em>.