Answer:
(-3,-20)
Step-by-step explanation:
4 +8x = y ...... equation (1)
6x - y = 2 ........equation(2)
from equation 2
6x - y = 2
6x -(4+8x) =2
6x - 4 + 8x = 2
+4 +4
6x - 8x = 6
-2x=6
divide by -2
x= -3
put x in equation (1) to solve for y
4 + 8x = y
4+8(-3)=y
4-24=y
-20=y
y= -20
solution = (-3,-20)
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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Answer:
Wdym
Step-by-step explanation:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
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