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NISA [10]
4 years ago
12

If P(A) = 0.3 and P(B) = 0.6 what is P(A or B) if the two events are independent?

Mathematics
1 answer:
Katena32 [7]4 years ago
6 0

Answer:

P(A or B) is 0.72

Step-by-step explanation:

Given : P(A) = 0.3 and P(B) = 0.6

To Find:P(A or B) = P(A∪B)

Solution :

We are given that A and B are two independent events

Property : If A and B are independent events then P(A \cap B) = P(A) \times P(B)

So, P(A \cap B) = P(A) \times P(B)

P(A \cap B) =0.3 \times 0.6

P(A \cap B) =0.18

Formula : P(A \cup B)=P(A)+P(B)-P(A \cap B)

P(A \cup B)=0.3+0.6-0.18

P(A \cup B)=0.72

Hence P(A or B) is 0.72

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Bill and Eugene left the airport at the same time. They traveled in opposite directions. Eugene traveled 21.1 km/h faster than B
gizmo_the_mogwai [7]

Answer:

56.3 kilometers per hour

Step-by-step explanation:

We know D = RT

where

D is distance

R is rate (speed)

T is time

Let's Bill's rate be "x". Thus using equation we can write:

D = xt

We know Eugene travelled 21.1 faster than Bill, so Eugene's rate is 21.1 + x. So we can write:

D = (21.1 + x)t

D = 21.1t + xt

Now, putting t = 1 in both since after 1 hour given, we have:

D = x(1)

D = x

and

D = 21.1(1) + x(1)

D = 21.1 + x

We know the sum of both the distance is 133.7, so we can write:

x + 21.1 + x = 133.7

Solving for x:

2x = 133.7 - 21.1

2x = 112.6

x = 112.6 / 2

x = 56.3 km/hr

This is Bill's rate: 56.3 kilometers per hour

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P(A)=.50 P(B)=.40, and P(A and B) = .15 what is P(a and B)
seropon [69]

Answer:

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Step-by-step explanation:

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3 years ago
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The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil
satela [25.4K]

The length of pencil A is 5 cm

<em><u>Solution:</u></em>

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

<em><u>The total length of pencils A, B and C is 29 cm</u></em>

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

<em><u>Pencil A is 11 cm shorter then pencil B</u></em>

x = y - 11 ------- eqn 2

<em><u>Pencil B is twice as long a pencil C</u></em>

y = 2z

z = \frac{y}{2} ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16

<em><u>Substitute y = 16 in eqn 2</u></em>

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0
3 years ago
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