Answer:
The forecast is accurate within plus or minus 3.2 units
Step-by-step explanation:
Mean Absolute Deviation is a statistical measure of dispersion from forecast. It measures accuracy level of predicted forecast, by averaging the difference between absolute value of each error from forecasted value.
MAD for a forecast states that : Forecast is accurate within the expected range variation of Mean Absolute Deviation.
So : If the MAD for a forecast is 3.2, we can say that - The forecast is accurate within plus or minus 3.2 units
Solution
For this case we can use the following formula:

Where:
P= 400800 = present value
A= future value
r= 0.055 interest rate
n= 4, number of times that the interest is compund in a year (quarterly)
t= 4 years
Replacing we got:

then the interest would be:
Answer:
A. 12
Step-by-step explanation:
Recall: one of the properties of a parallelogram is that the diagonals bisect each other. This means that:
LJ = 2(LW)
11x + 2 = 2(5x + 2)
11x + 2 = 10x + 4
11x + 2 - 2 = 10x + 4 - 2
11x = 10x + 2
11x - 10x = 10x + 2 - 10x
x = 2
✅LW = 5x + 2
Plug in the value of x
LW = 5(2) + 2
LW = 10 + 2 = 12
Sarah bought 3 first class tickets and 7 coach tickets.
Step-by-step explanation:
Given,
Number of people = 10
Total amount spent on tickets = $4830
Cost of each coach ticket = $270
Cost of each first class ticket = $980
Let,
x be the number of coach tickets
y be the number of first class tickets
According to given statement;
x+y=10 Eqn 1
270x+980y=4830 Eqn 2
Multiplying Eqn 1 by 270

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 710

Putting y=3 in Eqn 1

Sarah bought 3 first class tickets and 7 coach tickets.
Keywords: linear equation, elimination method
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The percentage of the semicircle shaded section is approximately 23,606 %.
The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

(1)
Where:
- Area of the half cross, in square centimeters.
- Area of the semicircle, in square centimeters.
- Percentage of the shaded section of the semicircle.
And the percentage of the shaded section is:
![r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100](https://tex.z-dn.net/?f=r%20%3D%20%5Cleft%5B1-%5Cfrac%7B4%20%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%2B4%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5Ccdot%20%282%5C%2Ccm%29%5E%7B2%7D%7D%7B0.5%5Ccdot%20%5Cpi%5Ccdot%20%2816%5C%2Ccm%5E%7B2%7D%2B4%5C%2Ccm%5E%7B2%7D%29%7D%20%5Cright%5D%5Ctimes%20100)

The percentage of the semicircle shaded section is approximately 23,606 %.
We kindly invite to check this question on percentages: brainly.com/question/15469506