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sergey [27]
3 years ago
7

An ordinary Fair die is a cube with the number 1 through 6 on the sides (represented by painted spots). imagine that such a die

is rolled twice in succession and the face values of the two dice rolls are added together. this sum is recorded as the outcome of a single trial of random experiment.
compute the probability of each of the following events. event A: the sum is greater than 7. B: the sum is an even number
Mathematics
1 answer:
aleksandrvk [35]3 years ago
7 0

Event A Answer: \frac{5}{12}

<u>Step-by-step explanation:</u>

sum greater than 7 leaves are the following combinations for 8, 9, 10, 11, and 12:

8 = 26, 35, 44, 51, 62  (5 possibilities)

9 = 36, 45, 54, 63  (4 possibilities)

10 = 46, 55, 64  (3 possibilities)

11 = 56, 65  (2 possibilities)

12 = 66  (1 possibility)

This is a total of 15 possibilities out of 36 total: \frac{15}{36} = \frac{5}{12}

***********************************************************************************

Event B Answer: \frac{1}{2}

<u>Step-by-step explanation:</u>

sum is an even number means both dice are odd or both dice are even.  That results in the following combinations:

11   13  15

22  24  26

31  33  35

42  44  46

51  53  55

62  64  66

This is a total of 18 possibilities out of 36 total: \frac{18}{36} = \frac{1}{2}

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Four functions are given below. Either the function is defined explicitly, or the entire graph of the function is shown.For each
Masja [62]

Summary of even and odd functions

A function f is even if the graph of f is symmetric with respect to the y-axis. Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f.

A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

From the definition itself, we see how can we test if the functions are even or odd.

- First graph (to the left)

From the graph, we see that the function is symmetric with respect to the y-axis because the left side (x<0) is a reflection (along the y-axis) of the right side (x>0), so it is an even function.

- Second graph (to the right)

From the graph, we see that the function is symmetric with respect to the origin, the left side (x<0) is a reflection (along with the origin) of the side to the right (x>0), so it is an odd function.

- First function (to the left)

The function:

g(x)=5x^2

is an even function because we see that:

g(-x)=5\cdot(-x)^2=5x^2=g(x)

- Second function (to the right)

The function:

h(x)=-2x^5+3x^3

is an odd function because we see that:

h(-x)=-2\cdot(-x)^5+3\cdot(-x)^3=-(-2x^5+3x^3)=-h(x)^{}

Summary

We have the following results:

- First function (to the left): even

- Second graph (to the right): odd

- First function (to the left): even

- Second function (to the right): odd

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