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Scilla [17]
3 years ago
11

After the expression (X^10)^3/5 is simplified as much as possible, x is raised to what exponent? a0

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

6

Step-by-step explanation:

erica [24]3 years ago
7 0

Answer:

6

Step-by-step explanation:

(x^10)^3/5

=x^(10×3/5)

=x^6

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Assume that x is a char variable has been declared and already given a value. Write an expression whose value is true if and onl
Lorico [155]

Answer:

bool b = isupper(x);

Step-by-step explanation:

I have written the expression for a char variable x.The isupper(x) will return true if the character x is upper case and false if the character x is lower case.

I have stored the returned value to a bool variable b .So the value of variable b will be true only when the x is in uppercase and false when b is lower case.

4 0
3 years ago
Round each to the place of the underlined digit. (1). 32.65 (The 6 is underlined), (2). 3.246 (The 4 is underlined), (3). 4.073
Roman55 [17]
1. 32.66
2.3.25
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8 0
3 years ago
Lucy Baker is analyzing demographic characteristics of two television programs, American Idol (population 1) and 60 Minutes (pop
creativ13 [48]

Answer:

Alternative hypothesis:\mu_1 -\mu_2 \neq 0

Or in the alternative way would be:

 Alternative hypothesis:\mu_1 \neq \mu_2

Step-by-step explanation:

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

On this case the claim that they want to test is: "The means for the two groups (American Idol and 60 Minutes) is the same". So we want to check if we have significant differences between the two means, so this needs to be on the alternative hypothesis and on the null hypothesis we need to have the complement of the alternative hypothesis.

Null hypothesis:\mu_1 -\mu_2 = 0

This null hypothesis can be expressed like this:

Null hypothesis:\mu_1 = \mu_2

Alternative hypothesis:\mu_1 -\mu_2 \neq 0

Or in the alternative way would be:

Alternative hypothesis:\mu_1 \neq \mu_2

4 0
3 years ago
3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
The amount of algae in a bloom, P, can be modeled by the equation P = t4 + 6t3 + 7t2 + 8t, where t is measured in weeks. When wi
Katyanochek1 [597]

(0,416, infinity) is the best answer

Thank you for your question, <u>your question is: The amount of algae in a bloom, P, can be modeled by the equation P = t4 + 6t3 + 7t2 + 8t, where t is measured in weeks. When will the population of algae be greater than 500?</u>

8 0
3 years ago
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