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zloy xaker [14]
3 years ago
13

The amount of algae in a bloom, P, can be modeled by the equation P = t4 + 6t3 + 7t2 + 8t, where t is measured in weeks. When wi

ll the population of algae be greater than 500?
Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0

(0,416, infinity) is the best answer

Thank you for your question, <u>your question is: The amount of algae in a bloom, P, can be modeled by the equation P = t4 + 6t3 + 7t2 + 8t, where t is measured in weeks. When will the population of algae be greater than 500?</u>

Marysya12 [62]3 years ago
6 0

Answer:

Much obliged to you for your inquiry, your inquiry is: The measure of green growth in a blossom, P, can be displayed by the condition P = t4 + 6t3 + 7t2 + 8t, where t is estimated in weeks. When will the number of inhabitants in green growth be more prominent than 500?

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A force of 200 Newtons is applied to a machine to lift a 1,000 Newtons load. What is the MA of the machine?
vovikov84 [41]

Answer:

5

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The mechanical advantage of a machine is the ratio of the force that you need to input to how much is outputted. 200:1000=1:5, meaning that the mechanical advantage is 5. Hope this helps!

3 0
3 years ago
1: Ken earned $176 from his part-time job this summer. He spent 25% of his money on games. ​He is going to donate 14 of the rema
tatiyna

The charity will receive $ 11

<h3><u>Solution:</u></h3>

Ken earned $176 from his part-time job this summer

Amount earned = $ 176

He spent 25% of his money on games

Therefore,

Money spent on games = 176 - 25 % of 176

\text{Money spent on games } = 176 - \frac{25}{100} \times 176\\\\\text{Money spent on games } = 176 - 0.25 \times 176\\\\\text{Money spent on games } = 176 - 44\\\\\text{Money spent on games } = 132

He is going to donate 1/4 of the remaining money to charity

Reamining amount = 176 - 132 = 44

Therefore,

Money\ given\ to\ charity = \frac{1}{4} \times 44 = 11

Thus he gave $ 11 to charity

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3 years ago
GEOMETRY: TANGENTS, SECANTS, AND CHORDS<br> can someone solve this with written work?
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masha68 [24]

Answer:

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