Answer: Counter, 0, 0.
Step-by-step explanation:
Think about a clock. The hand of a clock goes clockwise. When you tighten something (righty tighty) you spin it clockwise. You can rotate an object, lets say a square, clockwise. You can also rotate it counterclockwise, in the other direction. Therefore, you can rotate an object clockwise and <u>counter</u>clockwise.
You can rotate a figure around any point, such as the center of the figure, the origin, or anywhere else. One common place to rotate a figure around, such as a square, is the origin. This is the center of the coordinate plane. This point is not up, down, left, or right at all from the center. This coordinate is (0, 0). Therefore, the next two blank spaces should both be filled with 0.
The blank spaces should look like this:
One direction is clockwise and the other is <u>counter</u>clockwise.
...
This can be any coordinate point such as the origin which is at (<u> </u><u>0</u><u> </u>, <u>0</u><u> </u>)
Answer:

Step-by-step explanation:
This is a hard one
We have to use the rational root theorem
= 0
We have to find all the factors of a and d and put them in a fraction

We then plug them into the equation to see if any of them work
The equation isn't true when plugging 1, but is true when plugging in 1/2
factored form of 1/2 is (2x-1)
Then we divide the original equation by (2x-1) (you can use synthetic division or long division, it would be hard to type out the process for that) to get 
So now the equation is 
Solve the second half of this equation using the quadratic formula to get
and 
We already know the solution for the first half of the equation (1/2)
So the final answers are:

A=p(1+i/m)^mn
A=1,200×(1+0.03÷2)^(2×7)
A=1,478.11
Answer:
270 degrees counterclockwise rotation/ the last answer
Step-by-step explanation:
reflection over the y axis wouldn't work bc the shape would still be a horizontal rectangle
dilation would change the size of the shape
and translation wouldn't map it correctly bc it would still be turned the wrong way