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3 years ago

A pyramid with a rectangular base has how many more edges than vertices? List how many edges and vertices there are.

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

Edges:8
Vertices:5
8-5=3. There are 3 more edges than vertices.

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The domain and range of 5x squared plus 10x what is the domain and range of f of x equals 5x squared plus 10x

liberstina [14]

Answer:

Domain: set of all real numbers

Range: $y \geq -5$

Step-by-step explanation:

We have to find the domain and range of the function:

$f(x) =5x^2+10x$

This is a quadratic function, shape of a "U", that's called a parabola.

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Normally, any parabola in the form $ax^2+bx+c$ has domain as "all real numbers". This is the case for this problem as well, thus,

Domain = set of all real numbers

Now, for the range, we have to look at the minimum value of the function. So, the range would be y values greater than or equal to the minimum number. Lets find the minimum value of this function.

We have to find the value of x for which the minimum occurs by using the formula:

$x=\frac{-b}{2a} =\frac{-10}{2(5)} =-1$

Note: value of a is "5" and b is "10"

Now, we plug this into the function to find the minimum value:

$f(x)=5x^2+10x\\f(-1)=5(-1)^2 +10(-1)\\f(-1)=-5$

So, the range is set of all real numbers greater than or equal to -5.

8 0

3 years ago

, list the first five terms of each sequence. f(n + 1) = −2f(n) + 8 and f(1) = 1 for n ≥ 1

svet-max [94.6K]

Answer: 1, 7, 1, 7, 1.

Step-by-step explanation:

The given function : $f(n+1)=-2f(n)+8$ and f(1) = 1 for n ≥ 1

We put value of n=1,2,3,4 , we get

For n=1 , $f(2)=f(1+1)=-2f(1)+8=-1(1)+8=-1+8=7$

For n=2 , $f(3)=f(2+1)=-2f(2)+8=-1(7)+8=1$

For n=3 , $f(4)=f(3+1)=-2f(3)+8=-1(1)+8=7$

For n=4 , $f(5)=f(4+1)=-2f(4)+8=-1(7)+8=1$

Hence, the first five terms of the given sequence are 1, 7, 1, 7, 1.

7 0

3 years ago

4-2(3+2) ² 2. Help me plz i need the help

strojnjashka [21]

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

Hope it will help you :)

5 0

3 years ago

Read 2 more answers

I really need help with this please help best aswer gets brainliest

svet-max [94.6K]

Answer:

Relative frequency is 7.41% or 0.0741

Step-by-step explanation:

Given

The Attached Table

Required

Calculate the relative frequency of the class with lower limit 27

Relative Frequency is calculated by dividing individual frequency by the total frequency

Mathematically,

$Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}$

The total frequency of the given data is 6+8+4+2+5+2

$Total\ Frequency = 27$

The class with lower limit 27 has a frequency of 2;

Hence;

$Relative\ Frequency = \frac{Individual\ Frequency}{Total\ Frequency}$ becomes

$Relative\ Frequency = \frac{2}{27}$

$Relative\ Frequency = 0.07407407407$

$Relative\ Frequency = 0.0741$ (Approximated)

You may also leave your answer in percentage form

$Relative\ Frequency = 0.0741 * 100\%$

$Relative\ Frequency = 7.41 \%$

Hence, the relative frequency is 7.41% or 0.0741

7 0

3 years ago

Read 2 more answers

Estimate. Divide using the standard algor ithm and check.

KatRina [158]

image?????? im not sure

8 0

3 years ago