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igor_vitrenko [27]
4 years ago
15

How many protons, neutrons, and electrons are in 195Pt2+ ?

Chemistry
1 answer:
ladessa [460]4 years ago
4 0

Answer:

The answer to your question is Protons = 78, Neutrons = 117, Electrons = 76

Explanation:

                                ¹⁹⁵Pt²⁺

Protons are equal to the atomic number, Platinum has an atomic number of 78 so the number of protons = 78.

The number of neutrons = Mass number - Number of protons

                                         = 195 - 78

                                         = 117

The number of electrons is equal to the number of protons - two, we know this because of the 2+ exponent next to the Platinum symbol.

Number of electrons = 78 - 2

                                  = 76

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Answer:

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Explanation:

2100 j out   /   2500 j in  =  .84 = 84%

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6 0
3 years ago
What type of bond is Na3PO4?; Is Na3PO4 ionic or molecular?; Does Na3PO4 have ionic and covalent bonds?; Is Na3PO4 a polyatomic
Leni [432]

The type of the bond is present Na₃PO₄ is the ionic bond. the Na₃PO₄ is the ionic compound. yes the Na₃PO₄ is the polyatomic ion.

The Na₃PO₄ is Na⁺  and PO₄³⁻. the phosphorus is the non metal and the oxygen atom  is the non metal. the non meta and non meta form the covalent or molecular bond. the bond between the PO₄³⁻ bond is the covalent bond but the overall present in the Na₃PO₄ is the ionic bond . the bons in between the Na⁺  and PO₄³⁻ is the the ionic bond. the PO₄³⁻ id the polyatomic ion .

The bond between the positively charged ion and the negatively charged ion are called as the ionic bond and the compound form is the ionic compound.

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6 0
1 year ago
How are new kinds of matter formed in a chemial change?
shtirl [24]
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7 0
4 years ago
Read 2 more answers
Ferrophosphorus (Fe2P) reacts with pyrite (FeS2) producing iron(II) sulfide and a compound that is 27.87% P and 72.13% S by mass
k0ka [10]

Answer:

The molecular formula of the compound = P_4S_{10}

The empirical formula of the compound = P_2S_{5}

The balanced chemical equation for this reaction:

4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}

Explanation:

Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.

Molar mass of compound = 444.56 g/mol

Number of phosphorus atom = x

Number of sulfur atom = y

Atomic  mass of phosphorus  31 g/mol

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100

Phosphorus :

27.87\%=\frac{x\times 31 g/mol}{444.56 g/mol}\times 100

x = 4

Sulfur :

72.13\%=\frac{y\times 32 g/mol}{444.56 g/mol}\times 100

y = 10

The molecular formula of the compound = P_4S_{10}

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula of the compound = P_2S_{5}

The balanced chemical equation for this reaction:

4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}

8 0
4 years ago
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