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Hitman42 [59]
1 year ago
8

What type of bond is Na3PO4?; Is Na3PO4 ionic or molecular?; Does Na3PO4 have ionic and covalent bonds?; Is Na3PO4 a polyatomic

ion?
Chemistry
1 answer:
Leni [432]1 year ago
6 0

The type of the bond is present Na₃PO₄ is the ionic bond. the Na₃PO₄ is the ionic compound. yes the Na₃PO₄ is the polyatomic ion.

The Na₃PO₄ is Na⁺  and PO₄³⁻. the phosphorus is the non metal and the oxygen atom  is the non metal. the non meta and non meta form the covalent or molecular bond. the bond between the PO₄³⁻ bond is the covalent bond but the overall present in the Na₃PO₄ is the ionic bond . the bons in between the Na⁺  and PO₄³⁻ is the the ionic bond. the PO₄³⁻ id the polyatomic ion .

The bond between the positively charged ion and the negatively charged ion are called as the ionic bond and the compound form is the ionic compound.

To learn more about ionic bond here

brainly.com/question/29005103

#SPJ4

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At 79.0°C, the volume of a gas is 49.0 L. If the pressure remains constant, at what
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Answer:

At constant Pressure V /T = constant. sooooo

49 / 79 = 24.5 / T

T = 24.5 × 79/49 = 39.5°C

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Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

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Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of hea
Ksju [112]

Answer:

A. 0.00420 J/(gi°C)

Explanation:

i got it rigt

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