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Svetradugi [14.3K]
3 years ago
11

A boy 1.6 m tall casts a 2.4 m shadow. How tall is a nearby streetlight that casts a 7.2 m shadow?

Mathematics
1 answer:
Oxana [17]3 years ago
8 0
You basically need to set up a porporion:
1.6/2.4 = x/7.2
x=4.8
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You work on the 60th floor of 100 story building. You walk into your office and find a bomb sitting on your desk. It reads 90 se
lys-0071 [83]
Depends how strong the bomb is. If the bomb is weak then you would most likely go up 20-30 floors. If the bomb is in the middle go to the stair case and prepare for impact. If the bomb is strong go down 40 floors if possible. If none of this is possible to do and you don't know what to do about it then you must do the following:

Cut all of the wires in the bomb. Get the bomb near of a wall or a window. If it is a window then throw the bomb out of the window. If it is a wall put it as close to the wall as possible gather all your coworkers and run off of the floor.                                                                                 
 
    Hope this helps!

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3 years ago
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Jonathan is deciding between two truck rental companies. Company A
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Answer:

Jonathan is deciding between two truck rental companies. Company A

charges an initial fee of go for the rental plus $1 per mile driven

Company B charges an initial fee of $10 for the rental plus $1.50 per

mile driven. Let A represent the amount Company A would charge if

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would charge if Jonathan drives s miles, Graph each function and

determine which company would be cheaper if Jonathan needs to

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3 years ago
If an equation has one solution, what will the variable terms be<br>a. the same<br>b. different ​
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Answer:

If an equation has one solution, what will the variable terms be

b. different

8 0
2 years ago
1.17 − 0.07a + (−3.92a) What is this ????
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Remove parentheses.

17- 0.07a- 3.92a17−0.07a− 3.92a

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3 years ago
Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

3 0
3 years ago
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