All categories

3 years ago

The perimeter of a rectangle is 156 feet the length is 22 feet what is the width

Mathematics

1 answer:

dusya [7]3 years ago

8 0

Answer:

W value 56 ft

Step-by-step explanation:

The formula for the perimeter of a rectangle is

P = 2L + 2W

Here P = 156 ft = 2(22 ft) + 2W, or

78 ft = 22 ft + W

This yields the W value 56 ft

You might be interested in

Mia wrote an equation to approximate the total number of calories in the strawberries she was eating. She used the equation y =

kifflom [539]

Answer: I think b but don’t take my word

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

17+36=z-37 what is z

sp2606 [1]

Answer:

The correct answer is 90

Step-by-step explanation:

17 + 36= z- 37 ADD 17 AND 36

53= z-37 BRING 37 OVER TO 53 AND ADD

z = 90 FINAL ANSWER

8 0

3 years ago

Which of the following is graphed below?

nikklg [1K]

The function that is graphed is...
B.) y = |x - 3| - 4

Since the lines "|" in the function make it a V shape.
And when you graph the one point where the the 2 lines meet it is.
(-3, -4)

So this answer is correct. :P

Good Luck! :)

5 0

3 years ago

Read 2 more answers

You win a prize and are offered two choices. Which of the choices could be represented by a linear equation?

brilliants [131]

Answer:

choice b because it is constantly going up the same amount.

6 0

3 years ago

Read 2 more answers

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

$P(X>140)=P(Z>2)$

$P(X>140)=1-P(Z$

The Z-score value we get is from the Z-table,

$P(X>140)=1-0.9772$

$P(X>140)=0.0228$

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0

3 years ago