Step-by-step explanation:
The way that I would do it, would be to use the point distance formula to find the length of each side.
Distance formula: ![\sqrt{(x2-x1)^{2} (y2-y1) ^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x2-x1%29%5E%7B2%7D%20%28y2-y1%29%20%5E%7B2%7D%20%7D)
After you use this formula to find the length of all sides of the polygon, you would need to use the appropriate area formula to find the area of the polygon.
Area of Triangle: A= 1/2 base times height
Area of Rectangle: A= length times width
Area of Square: A= s^2 where s is the length of the side
Area of Parallelogram: A= base times height
Area of Trapezoid: A= 1/2 times height (base 1 + base 2) where base 1 and base 2 are the parallel sides
Area of Kite or Rhombus: A= 1/2 (diagonal 1 times diagonal 2)
Area of Regular Polygons: A= 1/2 (apothem times perimeter)
44 inches.
All you have to do is find out what 10% of 40 is then add it back to 40. In the case of finding 10% of something you just “chop” of the back number (or move the decimal place forward) so 10% of 40 is 4. The. 40+4=44.
You can also multiply fractions to find the percent of a number but that is not necessary in this case.
You can double the product of 9 and 4 to get to the product of 9 and 8
All of the angles combined =360 degrees
Vertical angles are congruent, so if angle 1 = 60, so does angle 3
Logically we have to find the measure of angle 4 and angle 2 combined and divide by 2
60 + 60 = 120
360 - 120 = 240
240 / 2 = 120
angle 4 = 120
angle 2= 120
angle 3 = 60
Answer:
(-5,-13)
Step-by-step explanation:
Find the vertex of the parabola y=1/5x^2+2x−8.
In this equation a=15 and b = 2.
x= -2/2(1/5) = -2/2/5 = -2/1 * 5/2 = -5
Substitute −5 into the equation y=1/5x^2+2x−8
y=1/5(−5)^2+2(−5)−8
y=5−10−8
y=−13
The vertex is (−5 , −13)