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Veronika [31]
4 years ago
10

Write the first five terms of the sequence in which the nth term is

Mathematics
1 answer:
8090 [49]4 years ago
7 0

Answer:

Third option 2,6,24,120,720

Step-by-step explanation:

Step 1

The first step is to simplify the expression for the nth term of this sequence using the definition of the factorial symbol. The simplification of this expression is done below,

a_n=\frac{(n+2)!}{(n+2)}=\frac{(n+2)\times(n+1)!}{(n+2)} =(n+1)!

Step 2

The second step is to use the substitute different values of n into the expression of the nth term to work out which sequence corresponds to the correct answer.

a_1=(1+1)!=2!=2\\a_2=(2+1)!=3!=6\\a_3=(3+1)!=4!=24\\a_4=(4+1)!=5!=120\\a_5=(5+1)!=6!=720

The terms of the sequence are {2,6,24,120,720}. The correct answer is the third option.

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Answer:

AB =  \frac{11}{2}

Step-by-step explanation:

Given

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And it gave us ⇒ \frac{2}{5}t=-\frac{7}{4}

Then multiply by five from both sides of equation form.

And it gave us ⇒ 5*\frac{2}{5}t=5(-\frac{7}{4})

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Next, divide by two from both sides of equation form.

And it gave us ⇒ \frac{2t}{2}=-\frac{35}{4/2}

Finally, simplify.

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Final answer: ⇒ \boxed{t=-35/8}

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