Answer:
Rock D.
Step-by-step explanation:
We can assume that the force that the catapult does is always the same.
So, here we need to remember Newton's second law:
F = m*a
force equals mass times acceleration.
Where acceleration is the rate of change of the velocity.
So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.
So, we can rewrite:
a = F/m
So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.
Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.
So we can assume that rock D is the correct option.
Answer:
A
Step-by-step explanation:
Just put x = 80 and y = 210 into the equation...
or put x = 40, y = 90.
A:
210 - 90 = 3(80-40)
120 = 120√
B:
210 + 90 = 3(80+40)
300 = 360×
C:
210 - 90 = 2.6(80-40)
120 = 104×
D:
210 + 90 = 2.6(80+40)
300 = 312×
Answer:
She forgot to flip the inequality sign when dividing both sides by -4
Answer:
3.14
Step-by-step explanation:
First find the circumference of the circle:
= Circumference.
= ![12\pi](https://tex.z-dn.net/?f=12%5Cpi)
Find the ratio of the angle in relation to the entire circle:
is what we have. So:
![\frac{30^o}{360^o} = \frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B30%5Eo%7D%7B360%5Eo%7D%20%3D%20%5Cfrac%7B1%7D%7B12%7D)
Use the ratio and multiply the circumference to find the length:
= ![\pi](https://tex.z-dn.net/?f=%5Cpi)
Round answer to the hundredth:
Answer:
<h3>AB ≈ 70m</h3>
Step-by-step explanation:
Check the attachment for the diagram.
You can see from the diagram that it is a right angled triangle with opposite side AB and adjacent side BC. Using SOH, CAH, TOA trig identity to get the length of AB. According to TOA;
tan 35° = opposite/adjacent
tan 35° = AB/BC
tan 35° = AB/100
AB = 100tan35°
AB = 100 * 0.7002
AB = 70.02m
Hence the distance across a lake between A and B is approximately 70m