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IRINA_888 [86]
3 years ago
13

Plzzz Help

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

60%

Step-by-step explanation:

Find the percentage doing 90/150 = 0.6. 1 represents 100%, so 0.6 = 60%.

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Graph 3x + 4y = -10
cricket20 [7]
First, isolate y on one side to find some information about the graph. 

3x+4y=-10 
4y=-10-3x
y=(-10-3x)/4 

Now find out the x and y intercepts of this equation;

(0)=(-10-3x)/4 
4x0=-10-3x 
0=-10-3x 
3x=-10 
x=-10/3 or -3.3333 (x-intercept) 

y=(-10-3(0))/4
4y=-10 
y=-10/4 or -5/2 = -2.5 (y-intercept) 

Plot these points onto your graph and connect the lines. 

I have attached a graph below, I'm sorry I couldn't do it on paper. 

Hope I helped :) 

8 0
4 years ago
A cable television compan is laying cable in an area with underground utilities. Two subdivisions are located on opposite sides
Schach [20]

Answer:

Step-by-step explanation:

Given:

Point Q = Q is on the north bank 1200 m east of P $40/m to lay cable underground and $80/m way to lay the cable.

Lets denote T be a point on north bank, therefore, point T is t m east and 100m north of P.

Note that 0 < t < 1200

Distance from P to T using Pythagoras theorem:

PT^2 = PQ^2 + QT^2

PT = √(t²+100²) = √(t²+10,000)

Distance from T to Q:

TQ = 1200 - t

From above, Cable from P to T is underwater, and costs $80/m to lay.

Cable from T to Q is underground, and costs $40/m to lay.

Total cost of the cable:

C(t) = 80√(t²+10,000) + 40(1200 - t)

Cost is at its minimum: when dC/dt = C'(t) = 0 and d^2C/dt^2 = C''(t) > 0

dC/dt = C'(t)

= 80 * 1/2 (t² + 10,000)^(-1/2) × 2t + 40 × (-1)

dC/dt = C'(t)

= 80t/√(t² + 10,000) - 40 = 0

80t/√(t² + 10,000) = 40

80t = 40√(t² + 10,000)

2t = √(t² + 10,000)

square both sides:

4t² = t² + 10,000

3t² = 10,000

t² = 10,000/3

t = 100/√3

≈ 57.735

d^2C/dt^2 =

C''(t) = [80√(t² + 10,000) - 80t × t/√(t²+10,000)] /√(t²+10,000)

C''(t) = [(80(t²+10,000) - 80t²) / √(t²+10,000)] /√(t²+10,000)

C''(t) = 800,000 / (t² + 10,000)^(3/2)

C''(t) > 0 for all t

Therefore C(t) is minimized at t = 100/√3

C(100/√3) = 80√(10,000/3 + 10,000) + 40 × (1200 - 100/√3)

= 80 √(40,000/3) + 48,000 - 4000/√3

= 16000/√3 + 48,000 - 4000/√3

= 48,000 + 12,000/√3

= 48,000 + 4,000√3

= 4000 (12 + √3)

≈ 54,928.20

Minimum cost is $54,928.20

This occurs when cable is laid underwater from point P to point T(57.735 m east and 100m north of P) and then underground from point T to point Q (1200 - 57.735)

= 1142.265 m

5 0
3 years ago
Solve by elimination <br>x+y= 0 <br>2x-y= 12​
dezoksy [38]

Answer:

m=2

Step-by-step explanation:

I calculated it sorry

5 0
3 years ago
Read 2 more answers
Type it down in the right order thanks
brilliants [131]

Answer:

$53.00 for 4 pounds

$13.25 for 1 pound

Step-by-step explanation:

6 0
3 years ago
PLEASEEEEEEE HELP with this question
nikklg [1K]

Answer:

second table

Step-by-step explanation:

Out of the 8 options on the spinner, 2 of them are 0's, 1 of them is a 1, 2 of them are 2's and 3 of them are 3's so the probability of spinning a 0, 1, 2 or 3 is 2/8, 1/8, 2/8 or 3/8 which becomes 0.25, 0.125, 0.25 or 0.375 respectively. Therefore, the answer is the second table.

3 0
3 years ago
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