Ask question

Ask question

All categories

3 years ago

14

Your favorite local band is selling merchandise and they have asked you to write an algebraic expression to represent their tota

l profit. The are selling t-shirts for $15 each and CDs for $5 each.
Write an expression to represent the total profit for t number of shirts sold and c number of CDs sold.
Evaluate your expression for 10 shirts and 25 CDs sold.

2 answers:

Yuki888 [10]3 years ago

6 0

Answer:

15t + 5c = b
$275

Step-by-step explanation:

Let "t' be the number of t-shirts bought.

Let "c" be the number of CDs bought.

Let b" be the total cost.

15t + 5c = b

We buy 10 t-shirts so t = 10.

We buy 25 CDs so c = 25.

We are trying to find b.

15t + 5c = b

15(10) + 5(25) = b

150 + 125 = b

275 = b

Best of Luck!

Setler [38]3 years ago

4 0

Answer:

<h2>15t + 5c = tp</h2><h2>tp = $275</h2><h2></h2>

Step-by-step explanation:

t-shirts for $15 = t

cd's for $5 = c

let tp = total profit

the algebraic expression would be:

15t + 5c = tp

-------------------------

evaluate the expression 15t + 5c = tp

for t = 10 and c = 25

plugin values into the formula:

15(10) + 5(25) = tp

tp = 150 + 125

tp = 275

therefore, the total profit is $275

You might be interested in

X+3/x-2 - 1-x/x =17/4<br>find the x with methods

Archy [21]

Step-by-step explanation:

x+3/x-2 - 1-x/x= 17/4

now let's put the expression on the upper side so it I'll be

x+3-x-2-1-x-x= 17×14

x-x-x-x+3-2-1= 238

+3-3= 238

= 238 answer

7 0

2 years ago

Read 2 more answers

A 200-gal tank contains 100 gal of pure water. At time t = 0, a salt-water solution containing 0.5 lb/gal of salt enters the tan

Artyom0805 [142]

Answer:

1) $\frac{dy}{dt}=2.5-\frac{3y}{2t+100}$

2) $y(t)=(50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}$

3) 98.23lbs

4) The salt concentration will increase without bound.

Step-by-step explanation:

1) Let $y$ represent the amount of salt in the tank at time t, where t is given in minutes.

Recall that: $\frac{dy}{dt}=rate\:in-rate\:out$

The amount coming in is $0.5\frac{lb}{gal}\times 5\frac{gal}{min}=2.5\frac{lb}{min}$

The rate going out depends on the concentration of salt in the tank at time t.

If there is $y(t)$ pounds of salt and there are $100+2t$ gallons at time t, then the concentration is: $\frac{y(t)}{2t+100}$

The rate of liquid leaving is is 3gal\min, so rate out is $=\frac{3y(t)}{2t+100}$

The required differential equation becomes:

$\frac{dy}{dt}=2.5-\frac{3y}{2t+100}$

2) We rewrite to obtain:

$\frac{dy}{dt}+\frac{3}{2t+100}y=2.5$

We multiply through by the integrating factor: $e^{\int \frac{3}{2t+100}dt }=e^{\frac{3}{2} \int \frac{1}{t+50}dt }=(50+t)^{\frac{3}{2} }$

to get:

$(50+t)^{\frac{3}{2} }\frac{dy}{dt}+(50+t)^{\frac{3}{2} }\cdot \frac{3}{2t+100}y=2.5(50+t)^{\frac{3}{2} }$

This gives us:

$((50+t)^{\frac{3}{2} }y)'=2.5(50+t)^{\frac{3}{2} }$

We integrate both sides with respect to t to get:

$(50+t)^{\frac{3}{2} }y=(50+t)^{\frac{5}{2} }+ C$

Multiply through by: $(50+t)^{-\frac{3}{2}}$ to get:

$y=(50+t)^{\frac{5}{2} }(50+t)^{-\frac{3}{2} }+ C(50+t)^{-\frac{3}{2} }$

$y(t)=(50+t)+ \frac{C}{(50+t)^{\frac{3}{2} }}$

We apply the initial condition: $y(0)=0$

$0=(50+0)+ \frac{C}{(50+0)^{\frac{3}{2} }}$

$C=-12500\sqrt{2}$

The amount of salt in the tank at time t is:

$y(t)=(50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}$

3) The tank will be full after 50 mins.

We put t=50 to find how pounds of salt it will contain:

$y(50)=(50+50)- \frac{12500\sqrt{2} }{(50+50)^{\frac{3}{2} }}$

$y(50)=98.23$

There will be 98.23 pounds of salt.

4) The limiting concentration of salt is given by:

$\lim_{t \to \infty}y(t)={ \lim_{t \to \infty} ( (50+t)- \frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }})$

As $t\to \infty$ , $50+t\to \infty$ and $\frac{12500\sqrt{2} }{(50+t)^{\frac{3}{2} }}\to 0$

This implies that:

$\lim_{t \to \infty}y(t)=\infty- 0=\infty$

If the tank had infinity capacity, there will be absolutely high(infinite) concentration of salt.

The salt concentration will increase without bound.

6 0

3 years ago

Choose ALL the right triangles.

11Alexandr11 [23.1K]

Answer:

Bottom left corner and bottom right corner

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Can someone answer this !

rodikova [14]

Answer:

11253

Step-by-step explanation:

the steps are described in the picture above

6 0

3 years ago

The ratio of boys to girls in the Science Club is 3:5. If there are 60 girls, how many boys are there?

maks197457 [2]

25 boys.

15/3 = 5

5*5=25

5 0

3 years ago

Read 2 more answers