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aev [14]
2 years ago
13

Write a slope-intercept equation of a line that is parallel to y = 2/3 x -4 and has a y-intercept of 8.

Mathematics
1 answer:
Leokris [45]2 years ago
7 0

Answer:

uuuuuuuguuguguu

Step-by-step explanation:

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2x^2=y\ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=\dfrac{y}{2}\\\\\boxed{x=\sqrt{\frac{y}{2}}}\\\\x=\dfrac{\sqrt{y}}{\sqrt2}=\dfrac{\sqrt{y}\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\to\boxed{x=\dfrac{\sqrt{2y}}{2}}\\\\\\\boxed{f(x)=2x^2\to f^{-1}(x)=\dfrac{\sqrt{2y}}{2}}
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Raphael is enrolled as a foreign exchange student. He is from Canada and is going to attend school in Texas. His mother sent him
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I pretty sure it would be 609.76
8 0
3 years ago
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Which equation, in slope-intercept form, passes through (–2, 4) and has a
kipiarov [429]

Answer:

y=3x+10

Step-by-step explanation:

First, put the equation into point-slope form.

y-y1=m(x-x1)

y-4=3(x+2)

Next, distribute 3 to (x+2) and simplify.

y-4=3x+6

y=3x+10

8 0
3 years ago
A function f is defined by f(x) = 2x - 3. By writing the full working, write the values of (a) f(0) (b) f(-2) (c) f(3) (d) f(-1)
AlladinOne [14]
A) f(x) = 2x - 3
f(0) = 2(0) - 3
f(0) = 0 - 3
f(0) = -3

b) f(x) = 2x - 3
f(-2) = 2(-2) - 3
f(-2) = -4 - 3
f(-2) = -7

c) f(x) = 2x - 3
f(3) = 2(3) - 3
f(3) = 6 - 3
f(3) = 3

d) f(x) = 2x - 3
f(-1) = 2(-1) - 3
f(-1) = -2 - 3
f(-1) = -5
6 0
3 years ago
(a) The perimeter of a rectangular garden is 304 m.
kupik [55]

Answer:

oof

Step-by-step explanation:

4 0
3 years ago
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